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Question #44318

Difficulty: 8/10 | 🟢 Free

The Question

A standard galvanic cell is constructed at 298 K: Anode: \cePt∣Sn2+(1M),Sn4+(1M)\ce{Pt | Sn^{2+}(1 M), Sn^{4+}(1 M)} Cathode: \cePt∣Tl+(1M),Tl3+(1M)\ce{Pt | Tl^{+}(1 M), Tl^{3+}(1 M)}

Given the standard reduction potentials and constants at 298 K: E\ceSn4+/Sn2+∘=+0.15 VE^\circ_{\ce{Sn^{4+}/Sn^{2+}}} = +0.15\text{ V} E\ceTl3+/Tl+∘=+1.26 VE^\circ_{\ce{Tl^{3+}/Tl^+}} = +1.26\text{ V} E\ceI2/I−∘=+0.54 VE^\circ_{\ce{I_2/I^-}} = +0.54\text{ V} Ksp(\ceTlI)=10−8K_{\text{sp}}(\ce{TlI}) = 10^{-8} 2.303RTF=0.06 V\frac{2.303RT}{F} = 0.06\text{ V}

Excess solid \ceKI\ce{KI} is added to the cathode compartment until the concentration of free \ceI−\ce{I^-} reaches exactly 1 M1\text{ M} at equilibrium. Solid \ceI2\ce{I_2} and \ceTlI\ce{TlI} are observed to precipitate. (Assume \ceI2\ce{I_2} separates as a solid with unit activity, ignore \ceI3−\ce{I_3^-} formation, and assume no volume change).

What is the new overall cell potential (EcellE_{\text{cell}}) and the equilibrium concentration of \ceTl3+\ce{Tl^{3+}} in the cathode compartment?

Options

  • A.

    1.35 V1.35\text{ V} and 1.0 M1.0\text{ M}

  • B.

    0.39 V0.39\text{ V} and 10−32 M10^{-32}\text{ M}

  • C.

    1.11 V1.11\text{ V} and 10−20 M10^{-20}\text{ M}

  • D.

    0.39 V0.39\text{ V} and 10−8 M10^{-8}\text{ M}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Inert Pair Effect|Spontaneity Criteria|Standard State Conditions

Why This Question Is Tricky

Common Mistakes

This question tests the 'Hidden Variable' of a spontaneous redox reaction occurring within a half-cell upon the addition of a precipitating agent.

Students often mechanically apply the Nernst equation using the KspK_{\text{sp}} to find the new concentration of the reduced species (\ceTl+\ce{Tl^+}), completely missing that the added anion (\ceI−\ce{I^-}) is a reducing agent capable of reacting with the highly oxidizing \ceTl3+\ce{Tl^{3+}} (a direct consequence of the Inert Pair Effect).

This shifts the potential-determining couple from \ceTl3+/Tl+\ce{Tl^{3+}/Tl^+} to \ceI2/I−\ce{I_2/I^-}.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterClassification of Elements and Periodicity in Properties - Class 11 Part 1
ConceptInert Pair Effect
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree