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Question #44274
The Question
The octahedral complex (where phen = 1,10-phenanthroline) exhibits a thermally induced Spin Crossover (SCO) because its crystal field splitting energy () is approximately equal to the pairing energy (). At , the complex exists in an enthalpy-minimized state, while at , it transitions to an entropy-maximized state. What are the spin-only magnetic moments () of the complex at and , respectively, and what is the theoretical electronic spin entropy change () for the transition from to per mole of the complex?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Magnetic Properties|Crystal Field Splitting (Octahedral)|Ligand Denticity Variations
Why This Question Is Tricky
Common Mistakes
The question tests the 'Spin State Crossover' (SCO) exception in Coordination Chemistry.
Students typically assign a fixed magnetic moment based on the spectrochemical series (assuming phenanthroline always forces a Low-Spin state).
The 'Hidden Variable' is the thermodynamic temperature dependence when .
The trap exposes the misconception that enthalpy (CFSE) solely dictates the spin state; at higher temperatures, the electronic and vibrational entropy () overrides the enthalpic penalty of populating anti-bonding orbitals, driving the transition from diamagnetic to paramagnetic.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Structure of Atom - Class 11 Part 1 |
| Concept | Magnetic Properties |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |