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Question #44271
The Question
Element has its highest energy electrons in a subshell characterized by and . The subshell is exactly half-filled in its ground state. Compound is the simplest primary mono-nuclear aromatic amine containing element . Consider the following derivatives of in an aqueous medium at :
I. Compound II. -Methyl derivative of III. -Methyl derivative of IV. -Methyl derivative of
Which of the following represents the correct decreasing order of basic strength () of these compounds?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Energy of Subshells (n+l rule)|Aniline Resonance Pitfalls|Ortho-Effect in Anilines
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to bridge fundamental atomic structure (using the n+l rule to identify Nitrogen) with advanced organic reaction mechanisms.
The primary trap is the 'Ortho-Effect' in substituted anilines.
Students relying solely on linear electronic effects (+I, +H) will incorrectly predict o-toluidine to be highly basic due to the proximity of the electron-donating methyl group.
However, the hidden variable is the steric inhibition of solvation of the conjugate acid.
This steric hindrance overrides the electronic resonance/inductive effects, making o-toluidine the least basic of the series, completely flipping the expected thermodynamic stability order.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Structure of Atom - Class 11 Part 1 |
| Concept | Energy of Subshells (n+l rule) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |