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Question #44260

Difficulty: 8/10 | 🟢 Free

The Question

The standard enthalpy of atomization of solid Chromium, \ceCr(s)\ce{Cr(s)}, at 298 K298\text{ K} is 397 kJ mol−1397\text{ kJ mol}^{-1}. The ground state electronic configuration of gaseous Chromium is an Aufbau exception. The energy required to excite the gaseous Chromium atom from its true ground state to the expected (but incorrect) Aufbau configuration [Ar]3d44s2[Ar] 3d^4 4s^2 is 96 kJ mol−196\text{ kJ mol}^{-1}.

A theoretical model calculates the mean \ceCr−Cl\ce{Cr-Cl} bond dissociation enthalpy in \ceCrCl3(g)\ce{CrCl_3(g)} to be 350 kJ mol−1350\text{ kJ mol}^{-1}. However, this model mistakenly defines the bond dissociation relative to the gaseous Chromium atom in the [Ar]3d44s2[Ar] 3d^4 4s^2 state.

Given that the standard enthalpy of formation of \ceCl(g)\ce{Cl(g)} is 121 kJ mol−1121\text{ kJ mol}^{-1}, calculate the true standard enthalpy of formation (ΔHf∘\Delta H^\circ_f) of \ceCrCl3(g)\ce{CrCl_3(g)} at 298 K298\text{ K}.

Options

  • A.

    −194 kJ mol−1-194\text{ kJ mol}^{-1}

  • B.

    −290 kJ mol−1-290\text{ kJ mol}^{-1}

  • C.

    −386 kJ mol−1-386\text{ kJ mol}^{-1}

  • D.

    −436 kJ mol−1-436\text{ kJ mol}^{-1}

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Correct Answer

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Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Aufbau Principle Exceptions|Standard State Conditions|Hess's Law Application

Why This Question Is Tricky

Common Mistakes

This problem tests the intersection of quantum mechanical electron configurations and macroscopic thermodynamics via Hess's Law.

Students often memorize Aufbau exceptions (like Cr being 3d54s13d^5 4s^1) but fail to realize that standard thermodynamic values (like ΔHat∘\Delta H^\circ_{at}) inherently reference this true ground state.

The primary trap (Option B) catches students who ignore the Aufbau exception, assuming 3d44s23d^4 4s^2 is the ground state and thus omitting the 96 kJ mol−196\text{ kJ mol}^{-1} excitation energy from the cycle.

It forces a rigorous application of state functions and reference states.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterStructure of Atom - Class 11 Part 1
ConceptAufbau Principle Exceptions
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree