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Question #44202
The Question
Consider the isoelectronic series of octahedral metal carbonyl complexes: , , , and . Their observed C-O stretching frequencies () are , , , and (not necessarily in this order). Separately, consider the silyl and alkyl amines, and . Which of the following options correctly identifies: (i) The of , (ii) The complex possessing the shortest M-C bond length, and (iii) The hybridization of the central nitrogen atom in and , respectively?
Options
- A.
, , and
- B.
, , and
- C.
, , and
- D.
, , and
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Bond Angle Variations|Valence Bond Theory Hybridization|Synergic Bonding in Carbonyls
Why This Question Is Tricky
Common Mistakes
The question tests the student's ability to move beyond rigid VSEPR models and apply Molecular Orbital theory concepts (back-bonding) to both coordination complexes and main-group compounds.
The trap lies in assuming that isoelectronic complexes have identical bond lengths/frequencies, or that analogous molecules like and share the same hybridization.
Students often overlook how synergic bonding dynamically alters bond order, bond length, and molecular geometry depending on the central atom's electronic environment.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Chemical Bonding and Molecular Structure - Class 11 Part 1 |
| Concept | Bond Angle Variations |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |