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Question #44197
The Question
In Molecular Orbital Theory, diatomic molecules like and exhibit s-p mixing, rendering the HOMO of weakly antibonding () and its LUMO as . When acts as a ligand in homoleptic octahedral complexes, synergic bonding dictates the C-O bond order.
Consider the isoelectronic complexes and . The standard reduction potentials are and . The anomalously negative for Mn reflects the profound exchange energy stabilization of its d-orbitals, which persists in the state, significantly lowering the energy of its electrons compared to .
Given that the C-O stretching frequency () for free is and for is , identify the most chemically accurate for from the given options.
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Molecular Orbital Mixing|E° (M²⁺/M) Anomalies
Why This Question Is Tricky
Common Mistakes
Tests the synthesis of MO theory (s-p mixing in CO), Coordination Chemistry (synergic back-bonding), and Periodic Trends ( anomalies).
Students often assume a linear trend in d-orbital energies across the 3d series.
The trap is failing to recognize that the anomalous stability of Mn's d-orbitals (evidenced by its ) drastically lowers the energy, widening the HOMO-LUMO gap for back-bonding.
Another trap is assuming back-bonding is completely absent in cations, which would incorrectly lead to a higher than free CO () due to pure -donation from the weakly antibonding HOMO.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Chemical Bonding and Molecular Structure - Class 11 Part 1 |
| Concept | Molecular Orbital Mixing |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |