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Question #44194
The Question
The hydration enthalpies () of ions in the 3d transition series exhibit a characteristic 'double-hump' curve due to significant Crystal Field Stabilization Energy (CFSE). For the Lanthanide series ( to ) at 298 K, the lanthanide contraction causes a steady decrease in ionic radius from to , significantly increasing the charge density. Considering the electronic structure of ions, what is the approximate magnitude of the CFSE contribution to their total hydration enthalpy, and what is the resulting shape of the versus Atomic Number curve?
Options
- A.
, Smooth monotonic curve
- B.
, Double-hump curve
- C.
, Smooth monotonic curve
- D.
, Double-hump curve
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Periodic Properties of Lanthanides|Crystal Field Splitting (Octahedral)|Coordination Compounds
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to differentiate between 3d and 4f coordination chemistry.
The trap is assuming that the lanthanide contraction (which increases charge density and theoretical ligand field strength) leads to a high CFSE and a 'double-hump' thermodynamic curve, similar to 3d metals.
The hidden variable is the deep shielding of 4f orbitals by and electrons, which renders ligand-field interactions (and thus CFSE) negligible.
This results in a smooth, monotonically increasing hydration enthalpy curve driven purely by electrostatics ().
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Classification of Elements and Periodicity in Properties - Class 11 Part 1 |
| Concept | Periodic Properties of Lanthanides |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |