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Question #44192

Difficulty: 8/10 | 🟢 Free

The Question

Mischmetal is a pyrophoric alloy containing ∼95%\sim 95\% lanthanides (predominantly \ce{Ce} and \ce{La}) and ∼5%\sim 5\% \ce{Fe}, hardened by interstitial elements like Carbon. The ability to accommodate interstitial atoms depends on the absolute size of the lattice voids, which is affected by the lanthanide contraction despite the packing fraction remaining constant.\n\nAssume both Cerium (γ\gamma-\ce{Ce}) and Lutetium (\ce{Lu}) crystallize in ideal face-centered cubic (fcc) lattices at 298 K298\text{ K}. The atomic radii are R\ceCe=183 pmR_{\ce{Ce}} = 183\text{ pm} and R\ceLu=173 pmR_{\ce{Lu}} = 173\text{ pm}. Carbon atoms (radius r\ceC=77 pmr_{\ce{C}} = 77\text{ pm}) are inserted into the octahedral voids of both lattices.\n\nAssuming hard-sphere behavior where the lattice expands uniformly along the edge to accommodate the carbon atom, calculate the difference in the required unit cell edge length distortion between Lutetium and Cerium, i.e., (Δa\ceLu−Δa\ceCe)(\Delta a_{\ce{Lu}} - \Delta a_{\ce{Ce}}).\n\n(Take 2=1.414\sqrt{2} = 1.414. Express your answer in pm).

Options

  • A.

    8.28 pm8.28\text{ pm}

  • B.

    4.14 pm4.14\text{ pm}

  • C.

    10.76 pm10.76\text{ pm}

  • D.

    28.28 pm28.28\text{ pm}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Periodic Properties of Lanthanides|Mischmetal Composition|Interstitial Compound Formation

Why This Question Is Tricky

Common Mistakes

This problem tests the intersection of Solid State Chemistry and Periodic Properties (Lanthanide Contraction).

The 'Hidden Variable' is that while the packing fraction (74%74\%) and relative void ratio (r/R=0.414r/R = 0.414) remain constant for fcc lattices, the absolute void size decreases across the lanthanide series.

Students often mistakenly calculate the radial distortion per atom (4.14 pm4.14\text{ pm}) instead of the total unit cell edge distortion (2×Δr=8.28 pm2 \times \Delta r = 8.28\text{ pm}).

This quantifies why early lanthanides (Ce, La) form more stable interstitial alloys (Mischmetal) than late lanthanides, as they require less lattice strain to accommodate hardeners like Carbon.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterClassification of Elements and Periodicity in Properties - Class 11 Part 1
ConceptPeriodic Properties of Lanthanides
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree