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Question #44167
The Question
Consider the hydration equilibria of propan-2-one (Acetone) and 1,1,1,3,3,3-hexafluoropropan-2-one (HFA) in aqueous solution at 298 K. Generally, ketone hydration is disfavored due to steric hindrance (B-strain) in the hybridized gem-diol. Consequently, the standard Gibbs free energy of hydration for acetone is . However, for HFA, the massive inductive withdrawal (-I) of the fluorine atoms and the relief of dipole repulsion completely overcome the steric B-strain, yielding a standard Gibbs free energy of hydration of . What is the ratio of their hydration equilibrium constants, , at 298 K? (Given: at 298 K)
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Hydrogen Bonding Competition|Hydrate Stability vs. Carbonyl|Steric Hindrance (B-Strain)
Why This Question Is Tricky
Common Mistakes
Students often apply the 'steric hindrance' (B-strain) heuristic universally, assuming bulky groups (like ) will always destabilize the hybridized gem-diol relative to the carbonyl.
However, in poly-fluorinated ketones like HFA, the intense inductive withdrawal (-I) drastically increases the electrophilicity of the carbonyl carbon.
Furthermore, hydration relieves the severe electrostatic repulsion between the highly polarized and bonds present in the planar state.
This electronic stabilization completely eclipses the steric B-strain, inverting the expected thermodynamic stability and serving as a classic exception to the rule.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Chemical Bonding and Molecular Structure - Class 11 Part 1 |
| Concept | Hydrogen Bonding Competition |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |