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Question #44156

Difficulty: 8/10 | 🟢 Free

The Question

Consider the isoelectronic and isostructural tetrahedral oxyanions \ceMoO42−\ce{MoO4^{2-}} and \ceWO42−\ce{WO4^{2-}} in aqueous medium at 298 K298\text{ K}. Evaluate the following four statements regarding their bonding characteristics and thermodynamic properties:

I. The formal resonance bond order of the \ceM−O\ce{M-O} bond in both \ceMoO42−\ce{MoO4^{2-}} and \ceWO42−\ce{WO4^{2-}} is 1.51.5. II. Experimentally, the bond length d\ceW−Od_{\ce{W-O}} is approximately equal to d\ceMo−Od_{\ce{Mo-O}}, which is shorter than expected from standard group trends due to the Lanthanide contraction. III. The \ceW−O\ce{W-O} bond exhibits stronger dπ−pπd\pi-p\pi overlap and greater covalent character than the \ceMo−O\ce{Mo-O} bond due to the relativistic expansion of the 5d5d orbitals. IV. \ceWO42−\ce{WO4^{2-}} is a stronger oxidizing agent than \ceMoO42−\ce{MoO4^{2-}} because the Lanthanide contraction drastically reduces the stability of the +6+6 oxidation state in Tungsten.

How many of the above statements are correct?

Options

  • A.

    1

  • B.

    2

  • C.

    3

  • D.

    4

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Bond Order in Resonance Hybrids|Post-Lanthanoid Radii Equality

Why This Question Is Tricky

Common Mistakes

This problem tests the student's ability to reconcile identical formal resonance bond orders with divergent physical properties.

The 'Hidden Variable' is the dual effect of the Lanthanide contraction (which equalizes radii and bond lengths) and relativistic 5d5d orbital expansion (which enhances dπ−pπd\pi-p\pi overlap and covalency in Tungsten).

Furthermore, Statement IV acts as a 'Lethal Trap' by baiting students into applying the p-block 'Inert Pair Effect' to d-block transition metals, where the trend is actually reversed (higher oxidation states are more stable down the group).

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterChemical Bonding and Molecular Structure - Class 11 Part 1
ConceptBond Order in Resonance Hybrids
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree