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Question #44132

Difficulty: 8/10 | 🟢 Free

The Question

An electrochemical cell is constructed at 298 K298 \text{ K} by coupling a Standard Hydrogen Electrode (SHE) as the anode with a cathode half-cell. The cathode half-cell consists of a platinum wire dipped into a 1.0 L1.0 \text{ L} aqueous solution prepared by completely dissolving 0.05 moles0.05 \text{ moles} of pure magnetite (\ceFe3O4(s)\ce{Fe3O4(s)}) in excess dilute \ceHClO4(aq)\ce{HClO4(aq)} under an inert atmosphere. The final concentration of \ceH+(aq)\ce{H+(aq)} in the solution is adjusted to 1.0 M1.0 \text{ M}.

Given: Standard reduction potential E\ceFe3+/Fe2+∘=0.770 VE^\circ_{\ce{Fe^{3+}/Fe^{2+}}} = 0.770 \text{ V} 2.303RTF=0.060 V\frac{2.303RT}{F} = 0.060 \text{ V} log⁡2=0.30\log 2 = 0.30

Assuming ideal behavior and no hydrolysis of metal ions, what is the electromotive force (EMF) of the cell?

Options

  • A.

    0.788 V0.788 \text{ V}

  • B.

    0.752 V0.752 \text{ V}

  • C.

    0.770 V0.770 \text{ V}

  • D.

    0.844 V0.844 \text{ V}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Average vs. Actual Oxidation State|Nernstian Redox Equilibrium|Electrode Potential Sign Conventions

Why This Question Is Tricky

Common Mistakes

The problem tests the conceptual boundary between solid-state average oxidation states and aqueous redox equilibria.

A common 'Lethal Collision' occurs when students treat \ceFe3O4\ce{Fe3O4} as having an average +8/3+8/3 oxidation state, leading them to construct a fictitious Nernstian equation for the overall dissolution (yielding 0.844 V0.844 \text{ V}).

Another frequent trap is confusing the stoichiometry of the inverse spinel structure, mistakenly assuming a 2:1 ratio of \ceFe2+\ce{Fe^{2+}} to \ceFe3+\ce{Fe^{3+}}, which inverts the reaction quotient QQ and results in 0.752 V0.752 \text{ V}.

The core principle is that electrochemical potential is strictly governed by the specific active redox sites (\ceFe3+/Fe2+\ce{Fe^{3+}/Fe^{2+}}) present in the solution.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterRedox Reactions - Class 11 Part 2
ConceptAverage vs. Actual Oxidation State
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree