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Question #44117

Difficulty: 8/10 | 🟢 Free

The Question

A 100 mL100 \text{ mL} aliquot of 0.1 M0.1 \text{ M} diprotic acid H2AH_2A (pKa1=4.0pK_{a1} = 4.0, pKa2=8.0pK_{a2} = 8.0) is titrated by adding drops of concentrated 10 M NaOH10 \text{ M } NaOH at 298 K298 \text{ K} (assume negligible volume change). The solution also contains 0.1 M AgNO30.1 \text{ M } AgNO_3. To detect the first equivalence point (formation of the amphiprotic ion HA−HA^-), an acidic indicator HInHIn (pKIn=6.0pK_{In} = 6.0) is added, making its total analytical concentration 1.0×10−4 M1.0 \times 10^{-4} \text{ M}. The indicator anion In−In^- forms a sparingly soluble red precipitate with Ag+Ag^+, \ceAgIn(s)\ce{AgIn(s)}, which acts as the visual endpoint. Given Ksp(\ceAgIn)=1.0×10−8K_{sp}(\ce{AgIn}) = 1.0 \times 10^{-8}. Assume Ag+Ag^+ does not precipitate or complex with any species of AA. Calculate the ratio of [HA−]/[H2A][HA^-]/[H_2A] at the moment the red precipitate first appears (apparent endpoint), and the theoretical pH of the first equivalence point.

Options

  • A.

    0.1, 6.0

  • B.

    1.0, 6.0

  • C.

    0.1, 4.0

  • D.

    10.0, 8.0

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Titration Indicators|Amphiprotic Ion pH|Common Ion Effect on Solubility

Why This Question Is Tricky

Common Mistakes

This problem tests the intersection of Acid-Base Titrations, Amphiprotic pH calculations, and Solubility Equilibria.

The 'Textbook Rule' assumes an indicator changes color at pH=pKInpH = pK_{In} (here, 6.0, which perfectly matches the true amphiprotic equivalence point).

However, the hidden variable is the common ion effect from Ag+Ag^+, which caps the maximum soluble concentration of In−In^- via the KspK_{sp} of \ceAgIn\ce{AgIn}.

This forces a physical state change (precipitation) at a much lower pH (3.0), overriding the standard weak acid-base equilibrium and causing a massive premature titration error.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterEquilibrium - Class 11 Part 1
ConceptTitration Indicators
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree