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Question #44117
The Question
A aliquot of diprotic acid (, ) is titrated by adding drops of concentrated at (assume negligible volume change). The solution also contains . To detect the first equivalence point (formation of the amphiprotic ion ), an acidic indicator () is added, making its total analytical concentration . The indicator anion forms a sparingly soluble red precipitate with , , which acts as the visual endpoint. Given . Assume does not precipitate or complex with any species of . Calculate the ratio of at the moment the red precipitate first appears (apparent endpoint), and the theoretical pH of the first equivalence point.
Options
- A.
0.1, 6.0
- B.
1.0, 6.0
- C.
0.1, 4.0
- D.
10.0, 8.0
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
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Concepts Behind This Question
Titration Indicators|Amphiprotic Ion pH|Common Ion Effect on Solubility
Why This Question Is Tricky
Common Mistakes
This problem tests the intersection of Acid-Base Titrations, Amphiprotic pH calculations, and Solubility Equilibria.
The 'Textbook Rule' assumes an indicator changes color at (here, 6.0, which perfectly matches the true amphiprotic equivalence point).
However, the hidden variable is the common ion effect from , which caps the maximum soluble concentration of via the of .
This forces a physical state change (precipitation) at a much lower pH (3.0), overriding the standard weak acid-base equilibrium and causing a massive premature titration error.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Equilibrium - Class 11 Part 1 |
| Concept | Titration Indicators |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |