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Question #44114

Difficulty: 8/10 | 🟢 Free

The Question

A half-cell consists of a Pt electrode immersed in an aqueous solution containing 0.01 M \ceCo2+0.01\text{ M } \ce{Co^{2+}} and 0.01 M \ceCo3+0.01\text{ M } \ce{Co^{3+}} at 298 K298\text{ K}. The initial reduction potential of this half-cell is E1E_1. Ammonia and ammonium chloride are then added to the half-cell such that the final equilibrium concentration of free \ceNH3\ce{NH3} is 0.1 M0.1\text{ M}. The new reduction potential of the half-cell is E2E_2. Given: E\ceCo3+/Co2+∘=+1.82 VE^\circ_{\ce{Co^{3+}/Co^{2+}}} = +1.82\text{ V}, log⁡β6 for \ce[Co(NH3)6]2+=4.0\log \beta_6 \text{ for } \ce{[Co(NH3)6]^{2+}} = 4.0, log⁡β6 for \ce[Co(NH3)6]3+=34.0\log \beta_6 \text{ for } \ce{[Co(NH3)6]^{3+}} = 34.0, and 2.303RTF=0.06 V\frac{2.303 RT}{F} = 0.06\text{ V}. Calculate the magnitude of the shift in the reduction potential, ∣E2−E1∣|E_2 - E_1|.

Options

  • A.

    1.68 V1.68\text{ V}

  • B.

    1.80 V1.80\text{ V}

  • C.

    1.74 V1.74\text{ V}

  • D.

    1.62 V1.62\text{ V}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Successive Equilibrium Constants|Oxidation State Traps|Variable Oxidation State Stability

Why This Question Is Tricky

Common Mistakes

This problem tests the boundary between memorized derived formulas and fundamental mass balance.

Students often memorize the shift in standard potential upon complexation as ΔE=0.059nlog⁡βoxβred\Delta E = \frac{0.059}{n} \log \frac{\beta_{\text{ox}}}{\beta_{\text{red}}}.

Applying this blindly yields 1.80 V1.80\text{ V}.

However, this formula assumes BOTH oxidation states are fully complexed.

By setting log⁡β6II=4.0\log \beta_6^{II} = 4.0 and [\ceNH3]=0.1 M[\ce{NH3}] = 0.1\text{ M}, the term β6II[\ceNH3]6=0.01\beta_6^{II}[\ce{NH3}]^6 = 0.01.

This means only ∼1%\sim 1\% of \ceCo2+\ce{Co^{2+}} is complexed.

Failing to verify mass balance leads to a calculated free [\ceCo2+][\ce{Co^{2+}}] of 1.0 M1.0\text{ M}, which is 100 times greater than the total cobalt added—a physical impossibility.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterEquilibrium - Class 11 Part 1
ConceptSuccessive Equilibrium Constants
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree