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Question #44091

Difficulty: 8/10 | 🟢 Free

The Question

An analytical chemist prepares a buffer solution at 50∘C50^\circ\text{C} by mixing a weak base BB (pKb=5.0pK_b = 5.0 at 50∘C50^\circ\text{C}) and its conjugate acid chloride BHClBHCl such that the solution exhibits maximum buffer capacity. Given that the ionic product of water at 50∘C50^\circ\text{C} is Kw=1.0×10−13K_w = 1.0 \times 10^{-13}, determine the exact pHpH of this buffer solution and its relative basicity, defined as ΔpH=pHbuffer−pHneutral\Delta pH = pH_{\text{buffer}} - pH_{\text{neutral}}, at this temperature.

Options

  • A.

    8.0, +1.5

  • B.

    9.0, +2.0

  • C.

    8.0, +1.0

  • D.

    9.0, +2.5

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Buffer Capacity and pH Range|Salt Hydrolysis Logic|Ionic Product of Water (Kw)

Why This Question Is Tricky

Common Mistakes

The 'Hidden Variable' being tested is the temperature dependence of the ionic product of water (KwK_w).

Students habitually rely on the standard 25∘C25^\circ\text{C} values (pKw=14.0pK_w = 14.0, neutral pH=7.0pH = 7.0).

At 50∘C50^\circ\text{C}, pKwpK_w drops to 13.013.0, which compresses the pHpH scale and shifts the neutral point to 6.56.5.

Trap B assumes standard 25∘C25^\circ\text{C} conditions entirely (pH=9.0,ΔpH=+2.0pH=9.0, \Delta pH=+2.0).

Trap C correctly calculates the new buffer pHpH (8.08.0) but forgets that the neutral point has also shifted, incorrectly subtracting 7.07.0 to get +1.0+1.0.

Trap D uses the standard pKwpK_w for the buffer calculation but the shifted neutral point.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterEquilibrium - Class 11 Part 1
ConceptBuffer Capacity and pH Range
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree