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Question #44066

Difficulty: 8/10 | 🟢 Free

The Question

Gaseous bromoethane (\ceCH3CH2Br\ce{CH3CH2Br}) undergoes a heterogeneous Swarts exchange with solid silver fluoride (\ceAgF\ce{AgF}) at 298 K298\text{ K} in a closed 2.0 L2.0\text{ L} vessel:

\ceCH3CH2Br(g)+AgF(s)<=>CH3CH2F(g)+AgBr(s)\ce{CH3CH2Br(g) + AgF(s) <=> CH3CH2F(g) + AgBr(s)}

The reaction occurs entirely on the solid surface. The intrinsic rate laws for the forward and reverse reactions are rf=kf[\ceCH3CH2Br][\ceAgF]effr_f = k_f [\ce{CH3CH2Br}][\ce{AgF}]_{eff} and rb=kb[\ceCH3CH2F][\ceAgBr]effr_b = k_b [\ce{CH3CH2F}][\ce{AgBr}]_{eff}. The vessel contains a mixed powder bed such that the effective surface site concentrations remain constant at [\ceAgF]eff=3.0 mol L−1[\ce{AgF}]_{eff} = 3.0\text{ mol L}^{-1} and [\ceAgBr]eff=1.0 mol L−1[\ce{AgBr}]_{eff} = 1.0\text{ mol L}^{-1}.

Given the intrinsic rate constants kf=2.0×10−2 L mol−1 s−1k_f = 2.0 \times 10^{-2}\text{ L mol}^{-1}\text{ s}^{-1} and kb=1.0×10−2 L mol−1 s−1k_b = 1.0 \times 10^{-2}\text{ L mol}^{-1}\text{ s}^{-1}, if 1.4 moles1.4\text{ moles} of \ceCH3CH2Br(g)\ce{CH3CH2Br(g)} are initially introduced into the vessel, determine the true thermodynamic equilibrium constant (KcK_c) and the equilibrium concentration of \ceCH3CH2F(g)\ce{CH3CH2F(g)}.

Options

  • A.

    Kc=6.0K_c = 6.0, [\ceCH3CH2F]eq=0.60 mol L−1[\ce{CH3CH2F}]_{eq} = 0.60\text{ mol L}^{-1}

  • B.

    Kc=2.0K_c = 2.0, [\ceCH3CH2F]eq=0.60 mol L−1[\ce{CH3CH2F}]_{eq} = 0.60\text{ mol L}^{-1}

  • C.

    Kc=2.0K_c = 2.0, [\ceCH3CH2F]eq=0.47 mol L−1[\ce{CH3CH2F}]_{eq} = 0.47\text{ mol L}^{-1}

  • D.

    Kc=6.0K_c = 6.0, [\ceCH3CH2F]eq=0.66 mol L−1[\ce{CH3CH2F}]_{eq} = 0.66\text{ mol L}^{-1}

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How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Homogeneous vs. Heterogeneous Equilibrium|Finkelstein and Swarts Exchange|Units of Rate Constant (k)

Why This Question Is Tricky

Common Mistakes

The question tests the fundamental distinction between the kinetic law of mass action (which includes all reacting species, including solid surface sites) and the thermodynamic equilibrium constant (where the activity of pure solids is exactly 1).

Students often erroneously calculate KcK_c as simply kf/kbk_f/k_b (yielding 2.0) by treating it as a homogeneous reaction, or they incorrectly include the solid concentrations in the KcK_c expression.

The trap exposes rote memorization of K=kf/kbK = k_f/k_b without accounting for the pseudo-first-order collapse caused by the constant solid surface area in heterogeneous systems.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterEquilibrium - Class 11 Part 1
ConceptHomogeneous vs. Heterogeneous Equilibrium
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree