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Question #44036
The Question
Consider the following two independent reaction sequences aimed at synthesizing sterically hindered primary amines:
\textbf{Reaction I:} Potassium phthalimide + 2-Bromo-2-phenylpropane Major nitrogen-containing product + Major non-nitrogenous organic product
\textbf{Reaction II:} 2-Methyl-2-phenylpropanamide Major organic product
Identify , , and .
Options
- A.
, ,
- B.
, ,
- C.
, ,
- D.
, ,
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Hoffmann Bromamide Rearrangement|Gabriel Phthalimide Synthesis|Ammonolysis Complexity
Why This Question Is Tricky
Common Mistakes
The question tests the critical limitations of primary amine synthesis methods.
Students often blindly apply the Gabriel phthalimide synthesis to any primary amine target.
However, Gabriel synthesis relies on an SN2 mechanism, which completely fails with tertiary alkyl halides due to severe steric hindrance, leading exclusively to E2 elimination.
Conversely, the Hoffmann Bromamide Rearrangement bypasses this steric limitation because the C-N bond is already formed in the amide precursor, and the subsequent 1,2-alkyl shift to the electron-deficient nitrogen accommodates bulky tertiary groups perfectly.
The trap is assuming both methods are universally interchangeable for primary amine synthesis.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Amines - Class 12 |
| Concept | Hoffmann Bromamide Rearrangement |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |