Start Learning Free

Before You Begin

Question #43944

Difficulty: 8/10 | 🟢 Free

The Question

An engineer models the transition from static to kinetic friction of a block using an equivalent RL circuit. The mechanical system consists of a block of mass m=2 kgm = 2 \text{ kg} on a rough horizontal surface with coefficients of static and kinetic friction μs=1.0\mu_s = 1.0 and μk=0.6\mu_k = 0.6, respectively. The block is subjected to a time-varying horizontal force F(t)=10t NF(t) = 10t \text{ N} and a viscous drag force Fv=bvF_v = bv, where b=4 N⋅s/mb = 4 \text{ N}\cdot\text{s/m}. Take g=10 m/s2g = 10 \text{ m/s}^2.

In the equivalent electrical model, velocity vv maps to current II, mass mm to inductance LL, and the applied force F(t)F(t) to a voltage source V(t)=10t VV(t) = 10t \text{ V}. The frictional forces are modeled by a non-linear diode in series with the inductor. The diode conducts no current until the voltage across it reaches a static breakdown threshold VsV_s. Upon conduction, it instantly transitions to a state with a constant forward voltage drop VkV_k and a dynamic resistance rdr_d.

Assume VsV_s maps to the maximum static friction, VkV_k maps to the kinetic friction, and rdr_d maps to the viscous drag coefficient bb. Determine the rate of change of current dIdt\frac{dI}{dt} immediately after the diode turns on, and the current II at t=2.5 st = 2.5 \text{ s}.

Options

  • A.

    4 A/s4 \text{ A/s} and (2−34e) A\left(2 - \frac{3}{4e}\right) \text{ A}

  • B.

    0 A/s0 \text{ A/s} and 54e A\frac{5}{4e} \text{ A}

  • C.

    4 A/s4 \text{ A/s} and 218 A\frac{21}{8} \text{ A}

  • D.

    0 A/s0 \text{ A/s} and (2−54e) A\left(2 - \frac{5}{4e}\right) \text{ A}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Dynamic Resistance (AC Resistance)|Kinetic Friction Transition

Why This Question Is Tricky

Common Mistakes

This question tests the formal analogy between the static-to-kinetic friction transition and a non-linear diode's piecewise I-V curve.

The 'Lethal Collision' occurs when students fail to account for the abrupt 'slip' in the opposing force (voltage drop) at the threshold.

A common mistake is assuming the diode maintains its 20 V20 \text{ V} breakdown voltage during conduction (analogous to static friction not dropping to kinetic), which incorrectly yields a continuous derivative dIdt=0\frac{dI}{dt} = 0 at turn-on and a significantly lower current.

Another trap is ignoring the dynamic resistance (viscous drag), treating the diode as an ideal constant voltage drop.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterSemiconductor Electronics: Materials, Devices, and Simple Circuits - Class 12
ConceptDynamic Resistance (AC Resistance)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree