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Question #43943

Difficulty: 8/10 | 🟢 Free

The Question

Consider a P-N junction diode operating under a forward bias voltage VV (in Volts) and carrying a current II (in Amperes). The charge carriers in the conduction band are modeled as an ideal gas of electrons following a Maxwell-Boltzmann distribution, with an adiabatic index γ\gamma. The diode's current-voltage relationship is given by I=I0exp⁡(eVkT)I = I_0 \exp\left(\frac{eV}{kT}\right), where ee is the elementary charge, kk is the Boltzmann constant, TT is the instantaneous temperature of the electron gas (in Kelvin), and I0I_0 is a constant reverse saturation current.

The junction is subjected to a rapid transient voltage fluctuation dVdV. The timescale of this fluctuation is much shorter than the lattice thermal diffusion time, meaning the electron gas undergoes an adiabatic process. During this process, the differential work done on each electron by the external voltage source is dW=edVdW = e dV.

Which of the following expressions gives the adiabatic dynamic resistance rd,ad=dVdIr_{d, ad} = \frac{dV}{dI} of the diode under these conditions?

Options

  • A.

    kTeI(1−(γ−1)eVkT)−1\frac{kT}{eI} \left( 1 - \frac{(\gamma-1)eV}{kT} \right)^{-1}

  • B.

    kTeI(1+(γ−1)eVkT)−1\frac{kT}{eI} \left( 1 + \frac{(\gamma-1)eV}{kT} \right)^{-1}

  • C.

    kTeI(1−γeVkT)−1\frac{kT}{eI} \left( 1 - \frac{\gamma eV}{kT} \right)^{-1}

  • D.

    kTeI\frac{kT}{eI}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Dynamic Resistance (AC Resistance)|Maxwell-Boltzmann Distribution|Adiabatic/Isothermal Processes via KTG

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of the Kinetic Theory of Gases with semiconductor device physics.

Students typically memorize the dynamic resistance of a diode as rd=kT/eIr_d = kT/eI (Option D), which implicitly assumes isothermal conditions where the carrier gas remains in thermal equilibrium with the lattice.

The trap lies in neglecting the thermo-electronic coupling during rapid (adiabatic) transients.

By applying the First Law of Thermodynamics to the electron gas, the work done by the external voltage source (edVe dV per particle) increases the internal energy and thus the temperature of the carriers.

This transient temperature shift modifies the differential of the Maxwell-Boltzmann distribution, introducing a γ\gamma-dependent correction factor to the dynamic resistance.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterSemiconductor Electronics: Materials, Devices, and Simple Circuits - Class 12
ConceptDynamic Resistance (AC Resistance)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree