Start Learning Free

Before You Begin

Question #43942

Difficulty: 8/10 | 🟢 Free

The Question

An ideal battery of EMF ε\varepsilon, a switch SS, an inductor LL, a resistor RR, and a special semiconductor device are connected in series. The semiconductor device is designed such that its macroscopic voltage drop VDV_D is dynamically governed by the relation VD=rd(I)IV_D = r_d(I) I, where II is the instantaneous current and rd(I)=dVdIr_d(I) = \frac{dV}{dI} is the small-signal dynamic resistance of an ideal P-N junction diode in forward bias (I≫IsI \gg I_s). The ideal diode follows the Shockley equation I=IseeV/kTI = I_s e^{eV/kT}, where ee is the elementary charge, kk is the Boltzmann constant, and TT is the absolute temperature. If the switch SS is closed at t=0t=0, which of the following expressions correctly represents the transient current I(t)I(t) in the circuit for t>0t > 0? (Assume ε>kTe\varepsilon > \frac{kT}{e} and the initial current is zero).

Options

  • A.

    I(t)=ε−kTeR(1−e−RLt)I(t) = \frac{\varepsilon - \frac{kT}{e}}{R} \left( 1 - e^{-\frac{R}{L}t} \right)

  • B.

    I(t)=εR(1−e−RLt)I(t) = \frac{\varepsilon}{R} \left( 1 - e^{-\frac{R}{L}t} \right)

  • C.

    I(t)=εR+kTeIs(1−e−(R+kTeIsL)t)I(t) = \frac{\varepsilon}{R + \frac{kT}{e I_s}} \left( 1 - e^{-\left(\frac{R + \frac{kT}{e I_s}}{L}\right)t} \right)

  • D.

    I(t)=εR(1−e−RLt)−Ise−eεkTI(t) = \frac{\varepsilon}{R} \left( 1 - e^{-\frac{R}{L}t} \right) - I_s e^{-\frac{e\varepsilon}{kT}}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Dynamic Resistance (AC Resistance)|Cell EMF vs Terminal Voltage|Transient Current in RL Circuit

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to couple microscopic semiconductor physics (dynamic resistance derived from the Shockley equation) with macroscopic transient circuit analysis.

The primary trap lies in the perceived mathematical complexity: students often assume that a current-dependent resistance rd(I)r_d(I) will result in an unsolvable non-linear differential equation and attempt incorrect approximations (like treating rdr_d as a constant evaluated at IsI_s, leading to Option C).

By rigorously applying the definition rd=dV/dIr_d = dV/dI, the II dependence perfectly cancels out in the voltage drop term VD=rd(I)IV_D = r_d(I)I, reducing the system to a linear ODE with a shifted EMF.

This penalizes rote memorization of RL formulas and rewards fundamental algebraic substitution and KVL application.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterSemiconductor Electronics: Materials, Devices, and Simple Circuits - Class 12
ConceptDynamic Resistance (AC Resistance)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree