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Question #43935

Difficulty: 8/10 | 🟢 Free

The Question

An inductor of inductance LL and a semiconductor device are connected in series to an ideal DC voltage source of EMF V=29I0R0V = \frac{2}{9} I_0 R_0. Due to rapid thermal feedback, the dynamic resistance of the semiconductor device depends on the instantaneous current ii as R(i)=R0(1−iI0)R(i) = R_0 \left(1 - \frac{i}{I_0}\right), where R0R_0 and I0I_0 are positive constants. The circuit is closed at t=0t=0. What is the total work done by the voltage source from t=0t=0 until the current reaches half of its steady-state value?

Options

  • A.

    29LI02ln⁡(98)\frac{2}{9} L I_0^2 \ln\left(\frac{9}{8}\right)

  • B.

    19LI02ln⁡(32)\frac{1}{9} L I_0^2 \ln\left(\frac{3}{2}\right)

  • C.

    49LI02ln⁡(43)\frac{4}{9} L I_0^2 \ln\left(\frac{4}{3}\right)

  • D.

    23LI02ln⁡(98)\frac{2}{3} L I_0^2 \ln\left(\frac{9}{8}\right)

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Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Transient Current in RL Circuit|Dynamic Resistance (AC Resistance)|Calculus

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to handle non-linear transient circuits, specifically invalidating the standard 1−e−t/τ1-e^{-t/\tau} exponential growth model.

Students often fall into the trap of attempting to define an 'average' time constant or incorrectly applying the standard formula W=12LI2+∫I2RdtW = \frac{1}{2}LI^2 + \int I^2R dt without accounting for the dynamic resistance R(i)R(i).

By coupling the thermal feedback into the resistance, the problem forces students to derive the governing non-linear differential equation from first principles and apply the Work-Energy theorem in its differential form (dW=Vidt=VidtdididW = Vi dt = Vi \frac{dt}{di} di) to bypass the explicit time dependence.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectromagnetic Induction - Class 12
ConceptTransient Current in RL Circuit
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree