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Question #43913

Difficulty: 8/10 | 🟢 Free

The Question

A straight bimetallic strip of length LL, width ww, and total thickness 2d2d (composed of two metals of equal thickness dd, identical Young's modulus, and thermal expansion coefficients α1\alpha_1 and α2\alpha_2 with α1>α2\alpha_1 > \alpha_2) is clamped at one end in a vacuum chamber at absolute zero. One of its large faces is uniformly bombarded by an effusive beam of monatomic ideal gas molecules (mass mm) escaping from a small hole of an oven. The gas inside the oven has a number density nn and the variance of the kinetic energy of an individual molecule in the oven is VV. The molecules strike the strip normally, stick to it, and transfer all their energy. The strip reaches a steady-state uniform temperature TsT_s by dissipating heat to the vacuum exclusively via a linearized heat loss mechanism, where the total power lost is Ploss=βLwTsP_{\text{loss}} = \beta L w T_s (β\beta is a known constant). Assuming the mechanical pressure of the gas beam is negligible compared to the thermal stress, what is the steady-state radius of curvature RR of the strip?

Options

  • A.

    (83)1/4dβ(α1−α2)nπmV3/2\left( \frac{8}{3} \right)^{1/4} \frac{d \beta}{(\alpha_1 - \alpha_2) n} \sqrt{\frac{\pi m}{V^{3/2}}}

  • B.

    (2048243)1/4dβ(α1−α2)nπmV3/2\left( \frac{2048}{243} \right)^{1/4} \frac{d \beta}{(\alpha_1 - \alpha_2) n} \sqrt{\frac{\pi m}{V^{3/2}}}

  • C.

    (6481)1/4dβ(α1−α2)nπmV3/2\left( \frac{64}{81} \right)^{1/4} \frac{d \beta}{(\alpha_1 - \alpha_2) n} \sqrt{\frac{\pi m}{V^{3/2}}}

  • D.

    (1283)1/4dβ(α1−α2)nπmV3/2\left( \frac{128}{3} \right)^{1/4} \frac{d \beta}{(\alpha_1 - \alpha_2) n} \sqrt{\frac{\pi m}{V^{3/2}}}

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Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Bimetallic Strip Curvature|Maxwell-Boltzmann Distribution|Approximation

Why This Question Is Tricky

Common Mistakes

This question tests the intersection of statistical mechanics and solid mechanics, specifically targeting the 'Energy Fluctuation' trap.

Students often incorrectly assume the average kinetic energy of molecules striking a wall from an effusive beam is the bulk average 32kT\frac{3}{2}kT.

However, the flux is velocity-dependent, skewing the distribution of striking molecules towards higher velocities and making their average energy 2kT2kT.

Furthermore, the problem requires deriving the temperature from the kinetic energy variance V=32(kT)2V = \frac{3}{2}(kT)^2, testing their understanding of the second moment of the Maxwell-Boltzmann distribution.

Failing to account for the velocity-weighted flux or miscalculating the variance leads directly to the trap options.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterThermal Properties of Matter - Class 11 Part 2
ConceptBimetallic Strip Curvature
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree