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Question #43904

Difficulty: 8/10 | 🟢 Free

The Question

A block of mass m=2 kgm = 2 \text{ kg} is placed on a rough inclined plane making an angle θ=37∘\theta = 37^\circ with the horizontal. The coefficient of static friction between the block and the plane is μs=0.8\mu_s = 0.8. An electromagnet is fixed such that it exerts a time-varying magnetic force Fmag=αi(t)F_{mag} = \alpha i(t) on the block in a direction perpendicular to and away from the inclined plane, where α=0.5 N/A\alpha = 0.5 \text{ N/A} and i(t)i(t) is the current. The electromagnet circuit has a total inductance L=4 HL = 4 \text{ H}, total resistance R=2 ΩR = 2 \text{ }\Omega, and is connected to a battery of emf V=10 VV = 10 \text{ V} via a switch. If the switch is closed at t=0t = 0, at what time tt will the block just begin to slide down the incline? (Take g=10 m/s2g = 10 \text{ m/s}^2, sin⁡37∘=0.6\sin 37^\circ = 0.6, cos⁡37∘=0.8\cos 37^\circ = 0.8)

Options

  • A.

    2ln⁡(53) s2 \ln \left( \frac{5}{3} \right) \text{ s}

  • B.

    2ln⁡(52) s2 \ln \left( \frac{5}{2} \right) \text{ s}

  • C.

    12ln⁡(53) s\frac{1}{2} \ln \left( \frac{5}{3} \right) \text{ s}

  • D.

    2ln⁡(2517) s2 \ln \left( \frac{25}{17} \right) \text{ s}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Kinetic Friction Transition|Transient Current in RL Circuit|Calculus (Integration)

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to couple transient circuit behavior with classical mechanics, specifically targeting the misconception of how external forces alter the normal force.

A common trap is assuming the magnetic force acts parallel to the incline to assist gravity, leading to an incorrect force balance (mgsin⁡θ+Fmag=μsmgcos⁡θmg \sin\theta + F_{mag} = \mu_s mg \cos\theta).

Another frequent error is misapplying the RL circuit equations, either by using the decay formula (i=I0e−Rt/Li = I_0 e^{-Rt/L}) instead of the growth formula, or by inverting the time constant (τ=R/L\tau = R/L instead of L/RL/R).

The problem requires recognizing that the limiting static friction is a continuous, time-dependent boundary condition modulated by the normal force.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterLaws of Motion - Class 11 Part 1
ConceptKinetic Friction Transition
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree