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Question #43903
The Question
A circuit consists of a DC voltage source , an ideal inductor , and a non-linear electronic device connected in series. The voltage-current characteristic of the device is given by (for ), where . At , the circuit is closed. Let be the time taken for the current to reach . After a long time, the current reaches a steady state. At this operating point, a small AC voltage with angular frequency is superimposed on the DC source. Let be the phase difference between the small-signal AC current and the AC voltage. Find the value of and the phase angle .
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Load Line Analysis|Series LCR Impedance Vector|Transient Current in RL Circuit
Why This Question Is Tricky
Common Mistakes
This question tests the ability to analyze non-linear circuits in both transient and small-signal AC steady states.
The primary trap lies in the AC phase calculation: students often incorrectly apply a stationary DC load line by using the static resistance , which yields an incorrect phase angle of .
For small AC signals superimposed on a DC bias, the device operates along the tangent of its V-I curve, requiring the dynamic resistance .
Additionally, the transient phase requires setting up and solving a first-order non-linear separable differential equation, testing rigorous application of Kirchhoff's laws beyond standard exponential LCR decays.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Semiconductor Electronics: Materials, Devices, and Simple Circuits - Class 12 |
| Concept | Load Line Analysis |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |