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Question #43903

Difficulty: 8/10 | 🟢 Free

The Question

A circuit consists of a DC voltage source V0=12 VV_0 = 12 \text{ V}, an ideal inductor L=2 HL = 2 \text{ H}, and a non-linear electronic device DD connected in series. The voltage-current characteristic of the device is given by VD=kI2V_D = k I^2 (for I>0I > 0), where k=3 V/A2k = 3 \text{ V/A}^2. At t=0t = 0, the circuit is closed. Let t1t_1 be the time taken for the current to reach 1 A1 \text{ A}. After a long time, the current reaches a steady state. At this operating point, a small AC voltage v(t)=v0sin⁡(ωt)v(t) = v_0 \sin(\omega t) with angular frequency ω=6 rad/s\omega = 6 \text{ rad/s} is superimposed on the DC source. Let ϕ\phi be the phase difference between the small-signal AC current and the AC voltage. Find the value of t1t_1 and the phase angle ϕ\phi.

Options

  • A.

    16ln⁡(3) s,  π4\frac{1}{6} \ln(3) \text{ s}, \; \frac{\pi}{4}

  • B.

    16ln⁡(3) s,  tan⁡−1(2)\frac{1}{6} \ln(3) \text{ s}, \; \tan^{-1}(2)

  • C.

    23ln⁡(3) s,  π4\frac{2}{3} \ln(3) \text{ s}, \; \frac{\pi}{4}

  • D.

    23ln⁡(3) s,  tan⁡−1(2)\frac{2}{3} \ln(3) \text{ s}, \; \tan^{-1}(2)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Load Line Analysis|Series LCR Impedance Vector|Transient Current in RL Circuit

Why This Question Is Tricky

Common Mistakes

This question tests the ability to analyze non-linear circuits in both transient and small-signal AC steady states.

The primary trap lies in the AC phase calculation: students often incorrectly apply a stationary DC load line by using the static resistance Rstatic=VD/I0=6  ΩR_{static} = V_D / I_0 = 6 \; \Omega, which yields an incorrect phase angle of tan⁡−1(2)\tan^{-1}(2).

For small AC signals superimposed on a DC bias, the device operates along the tangent of its V-I curve, requiring the dynamic resistance rd=dVD/dI=12  Ωr_d = dV_D/dI = 12 \; \Omega.

Additionally, the transient phase requires setting up and solving a first-order non-linear separable differential equation, testing rigorous application of Kirchhoff's laws beyond standard exponential LCR decays.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterSemiconductor Electronics: Materials, Devices, and Simple Circuits - Class 12
ConceptLoad Line Analysis
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree