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Question #43893
The Question
A large tank is filled with a transparent liquid of density , surface tension , and refractive index . A narrow vertical capillary tube of inner radius is connected to the bottom of the tank and bends upwards, forming a U-tube system. The open top of the capillary tube is at a vertical distance below the free surface of the liquid in the large tank. The liquid bulges out of the top of the capillary tube, forming a convex spherical meniscus pinned at the tube's edge. A small luminous object is placed inside the capillary tube at a depth below the pole of the meniscus. When viewed from above along the axis of the tube, the light rays emerging from the meniscus into the air are parallel. Assuming and all quantities are in consistent SI units, what is the required depth ?
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Optical Instrument Magnification|Capillary Rise Mechanics|Binomial Approximation
Why This Question Is Tricky
Common Mistakes
This question tests the coupling of hydrostatics, surface tension, and optics.
The primary trap lies in the student's assumption about the meniscus geometry and the focal length of a single refracting surface.
Students often incorrectly assume the meniscus is perfectly hemispherical () simply because it is in a capillary tube, ignoring the hydrostatic pressure head that dictates the actual radius of curvature via the Young-Laplace equation.
Furthermore, students frequently misapply the thin lens formula instead of the correct single-surface refraction condition , missing the factor of because the object is immersed in the denser medium.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Ray Optics and Optical Instruments - Class 12 |
| Concept | Optical Instrument Magnification |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |