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Question #43884

Difficulty: 8/10 | 🟢 Free

The Question

A rigid superconducting square coil of mass mm, side length aa, and self-inductance LL is pivoted freely about its top horizontal edge. The coil is placed in a uniform vertical magnetic field BB directed downwards. When the coil hangs vertically (θ=0\theta = 0), its plane is vertical. Initially, the coil is held at a small angle θ0\theta_0 with the vertical, and the current in the coil is zero. It is then released from rest. Find the maximum kinetic energy of the coil during its subsequent motion. Assume θ0\theta_0 is small enough that sin⁡θ≈θ\sin\theta \approx \theta and cos⁡θ≈1\cos\theta \approx 1, and let gg be the acceleration due to gravity.

Options

  • A.

    m2g2aLθ024(mgL+2B2a3)\frac{m^2 g^2 a L \theta_0^2}{4 (m g L + 2 B^2 a^3)}

  • B.

    (mgaL+2B2a4)θ024L\frac{(m g a L + 2 B^2 a^4) \theta_0^2}{4 L}

  • C.

    14mgaθ02\frac{1}{4} m g a \theta_0^2

  • D.

    m2g2aLθ022(mgL+B2a3)\frac{m^2 g^2 a L \theta_0^2}{2 (m g L + B^2 a^3)}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Series LCR Impedance Vector|Transient Current in RL Circuit|Physical Pendulum Inertia

Why This Question Is Tricky

Common Mistakes

The core trap lies in the misapplication of Faraday's Law for superconducting circuits.

Students often write the induced EMF as E=Ba2θ˙\mathcal{E} = B a^2 \dot{\theta} and equate it to LdidtL \frac{di}{dt}, incorrectly integrating to Li=Ba2θL i = B a^2 \theta by assuming the integration constant is zero.

This ignores the initial condition where the coil is released from θ0\theta_0 with zero current.

Consequently, they formulate the magnetic potential energy as 12B2a4Lθ2\frac{1}{2} \frac{B^2 a^4}{L} \theta^2, which shifts the equilibrium position to θ=0\theta=0 and leads to an incorrect maximum kinetic energy (Option B).

The problem rigorously tests the understanding that in a zero-resistance circuit, it is the total flux that is strictly conserved from the moment of release, creating a shifted harmonic oscillator.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterAlternating Current - Class 12
ConceptSeries LCR Impedance Vector
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree