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Question #43868

Difficulty: 8/10 | 🟢 Free

The Question

A rigid massless rod of length LL has a point charge +q+q of mass mm attached to one end and a point charge −q-q attached to the other end. The rod is pivoted at the −q-q end (which is fixed at the origin) and is free to rotate in the xyxy-plane. A torsional spring of stiffness CC is connected to the pivot, exerting a restoring torque τs=−Cθ\tau_s = -C\theta when the rod is at an angle θ\theta with the positive xx-axis. The entire system is immersed in a non-uniform electric field given by E⃗=E0(1+αx)i^\vec{E} = E_0(1 + \alpha x)\hat{i}, where E0E_0 and α\alpha are positive constants. If the rod is slightly displaced from its stable equilibrium position at θ=0\theta = 0, what is the angular frequency ω\omega of the resulting small oscillations?

Options

  • A.

    C+qE0L(1+αL)mL2\sqrt{\frac{C + qE_0L(1 + \alpha L)}{mL^2}}

  • B.

    C+qE0L(1+αL2)mL2\sqrt{\frac{C + qE_0L\left(1 + \frac{\alpha L}{2}\right)}{mL^2}}

  • C.

    C+qE0LmL2\sqrt{\frac{C + qE_0L}{mL^2}}

  • D.

    qE0L(1+αL)mL2\sqrt{\frac{qE_0L(1 + \alpha L)}{mL^2}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Dipole Potential Angular Dependence|SHM Definition via Differential Equation|Effective Spring Constant

Why This Question Is Tricky

Common Mistakes

This question tests the rigorous application of the effective spring constant keff=d2U/dθ2k_{eff} = d^2U/d\theta^2 in non-uniform fields.

A common trap is to assume the electrostatic restoring torque is simply τ=−pEeffsin⁡θ\tau = -pE_{eff}\sin\theta, and incorrectly evaluate the electric field at the dipole's center of mass (x=L/2x = L/2), leading to an erroneous term (1+αL/2)(1 + \alpha L/2).

Another trap is ignoring the field gradient entirely for the torque calculation.

By forcing students to Taylor expand the exact potential energy function (or calculate the exact torque via r⃗×F⃗\vec{r} \times \vec{F}), the problem differentiates those who rely on memorized uniform-field formulas (U=−pEcos⁡θU = -pE\cos\theta) from those who build the differential equation from first principles.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptDipole Potential Angular Dependence
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree