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Question #43858

Difficulty: 8/10 | 🟢 Free

The Question

A uniform thick string of mass MM and length LL is suspended from the ceiling of an elevator. A block of mass 3M3M is attached to the lower end of the string. The elevator is accelerating upwards with a constant acceleration a=g3a = \frac{g}{3}, where gg is the acceleration due to gravity. A small transverse wave pulse is generated at the lower end of the string. What is the time taken by the wave pulse to reach the ceiling of the elevator?

Options

  • A.

    3Lg(2−3)\sqrt{\frac{3L}{g}} (2 - \sqrt{3})

  • B.

    2Lg(2−3)2\sqrt{\frac{L}{g}} (2 - \sqrt{3})

  • C.

    12Lg\frac{1}{2}\sqrt{\frac{L}{g}}

  • D.

    3Lg(2+3)\sqrt{\frac{3L}{g}} (2 + \sqrt{3})

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

String Tension and Wave Speed|Frame of Reference Dependency|Vector Cross-Products

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to synthesize wave mechanics with non-inertial frame dynamics and distributed loads.

The primary trap is the assumption of a constant wave speed v=T/μv = \sqrt{T/\mu}.

Students often incorrectly use the tension at the bottom (or top) as a constant value throughout the string, failing to recognize that the string's own mass creates a tension gradient T(x)T(x).

Furthermore, students who do recognize the gradient often forget to apply the pseudo-force (inertial force) due to the elevator's acceleration, incorrectly using gg instead of geff=g+ag_{\text{eff}} = g + a.

By forcing the integration of a spatially dependent wave speed in an accelerating frame, the problem filters out rote memorization of standard wave formulas.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWaves - Class 11 Part 2
ConceptString Tension and Wave Speed
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree