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Question #43857
The Question
A metallic rod of length , uniform density , Young's modulus , and coefficient of linear thermal expansion is rigidly clamped between two immovable walls at and . The cross-sectional area of the rod varies linearly from at to at . Initially, the rod is in an unstrained state at temperature . The temperature of the rod is then uniformly decreased by . A small transverse wave pulse is generated at the end . Assuming the dimensional changes due to thermal contraction are negligible for calculating the wave speed and density, what is the time taken by the pulse to reach the other end ?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
String Tension and Wave Speed|Thermal Stress in Constrained Rods|Integration
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to couple thermal stress with wave mechanics in a non-uniform medium.
The primary trap lies in the assumption that thermal tension can be calculated using a local or average cross-sectional area (e.g., ).
Students often misapply Hooke's Law by failing to recognize that in a statically determinate constrained system with varying cross-section, the tension is uniform, but the stress varies.
Consequently, the total zero-displacement boundary condition must be enforced via an integral of the local strain .
Furthermore, students must correctly identify that the linear mass density also varies with position, requiring a second integration to find the wave transit time.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Waves - Class 11 Part 2 |
| Concept | String Tension and Wave Speed |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |