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Question #43857

Difficulty: 8/10 | 🟢 Free

The Question

A metallic rod of length LL, uniform density ρ\rho, Young's modulus YY, and coefficient of linear thermal expansion α\alpha is rigidly clamped between two immovable walls at x=0x=0 and x=Lx=L. The cross-sectional area of the rod varies linearly from A0A_0 at x=0x=0 to 2A02A_0 at x=Lx=L. Initially, the rod is in an unstrained state at temperature θ0\theta_0. The temperature of the rod is then uniformly decreased by Δθ\Delta\theta. A small transverse wave pulse is generated at the end x=0x=0. Assuming the dimensional changes due to thermal contraction are negligible for calculating the wave speed and density, what is the time tt taken by the pulse to reach the other end x=Lx=L?

Options

  • A.

    2L3(22−1)ρln⁡(2)YαΔθ\frac{2L}{3} (2\sqrt{2} - 1) \sqrt{\frac{\rho \ln(2)}{Y \alpha \Delta\theta}}

  • B.

    2L3(22−1)ρYαΔθ\frac{2L}{3} (2\sqrt{2} - 1) \sqrt{\frac{\rho}{Y \alpha \Delta\theta}}

  • C.

    LρYαΔθL \sqrt{\frac{\rho}{Y \alpha \Delta\theta}}

  • D.

    Lρln⁡(2)YαΔθL \sqrt{\frac{\rho \ln(2)}{Y \alpha \Delta\theta}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

String Tension and Wave Speed|Thermal Stress in Constrained Rods|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to couple thermal stress with wave mechanics in a non-uniform medium.

The primary trap lies in the assumption that thermal tension TT can be calculated using a local or average cross-sectional area (e.g., T=YA0αΔθT = Y A_0 \alpha \Delta\theta).

Students often misapply Hooke's Law by failing to recognize that in a statically determinate constrained system with varying cross-section, the tension is uniform, but the stress varies.

Consequently, the total zero-displacement boundary condition must be enforced via an integral of the local strain ϵ(x)=T/(A(x)Y)−αΔθ\epsilon(x) = T/(A(x)Y) - \alpha \Delta\theta.

Furthermore, students must correctly identify that the linear mass density μ(x)\mu(x) also varies with position, requiring a second integration to find the wave transit time.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWaves - Class 11 Part 2
ConceptString Tension and Wave Speed
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree