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Question #43850

Difficulty: 8/10 | 🟢 Free

The Question

A horizontal conducting rod of mass m=0.1 kgm = 0.1 \text{ kg} and length l=1 ml = 1 \text{ m} is suspended by a vertical ideal spring of spring constant k=6 N/mk = 6 \text{ N/m}. The rod is placed in a uniform horizontal magnetic field B=0.8 TB = 0.8 \text{ T} perpendicular to its length and the direction of motion. The ends of the rod are connected to a stationary external circuit containing a resistor R=1 ΩR = 1 \ \Omega and an inductor L=0.1 HL = 0.1 \text{ H} in series. The system is set into small vertical oscillations. The vertical displacement x(t)x(t) of the rod can be expressed as a sum of a purely exponentially decaying term and an exponentially decaying oscillatory term. What is the time constant τ\tau for the decay of the amplitude of the oscillatory term? (The amplitude of the oscillatory term decays as A0e−t/τA_0 e^{-t/\tau}).

Options

  • A.

    0.50 \text{ s}

  • B.

    0.3125 \text{ s}

  • C.

    0.70 \text{ s}

  • D.

    0.10 \text{ s}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Vertical Oscillations|L-C Circuit Analogy|Transient Current in RL Circuit

Why This Question Is Tricky

Common Mistakes

This question tests the ability to analyze a coupled electromechanical system where the damping is frequency-dependent due to an inductive load.

A common trap is treating the system as a simple underdamped oscillator with a constant damping coefficient b=B2l2/Rb = B^2 l^2 / R (ignoring the inductor's back-EMF), which leads to an incorrect time constant of 0.3125 s0.3125 \text{ s}.

Another trap is attempting to calculate an 'effective' mass and damping at the undamped natural frequency, yielding 0.70 s0.70 \text{ s}.

The rigorous approach requires setting up the coupled differential equations and solving the resulting 3rd-order characteristic polynomial.

The inductive load fundamentally alters both the effective mass and the decay rate, creating a transient response that cannot be modeled by standard constant-coefficient approximations.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterOscillations - Class 11 Part 2
ConceptVertical Oscillations
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree