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Question #43831

Difficulty: 8/10 | 🟢 Free

The Question

A heavy nucleus of mass number AA undergoes symmetric fission into two identical nuclei of mass number A/2A/2. The binding energy per nucleon, B(A)B(A), in this mass region has a constant negative gradient given by dBdA=−γ\frac{dB}{dA} = -\gamma (where γ>0\gamma > 0). The fission event occurs entirely within a semiconductor detector micro-pixel of constant heat capacity CC, initially at temperature T0T_0. The fission fragments are completely stopped within the pixel, and all the released energy QQ is rapidly converted into heat, raising the pixel's temperature uniformly to TfT_f. The detector measures the energy by generating electron-hole pairs. Assume the energy required to create one electron-hole pair is exactly equal to the semiconductor's band gap EgE_g at the final temperature TfT_f. If the band gap decreases with temperature as Eg(T)=Eg0−β(T−T0)E_g(T) = E_{g0} - \beta(T - T_0) (where β>0\beta > 0 and Eg0E_{g0} is the band gap at T0T_0), which of the following expressions gives the total number of electron-hole pairs NN generated by this single fission event?

Options

  • A.

    γA2C2CEg0−βγA2\frac{\gamma A^2 C}{2 C E_{g0} - \beta \gamma A^2}

  • B.

    γA2C2CEg0+βγA2\frac{\gamma A^2 C}{2 C E_{g0} + \beta \gamma A^2}

  • C.

    γA22Eg0\frac{\gamma A^2}{2 E_{g0}}

  • D.

    2γA2CCEg0−2βγA2\frac{2 \gamma A^2 C}{C E_{g0} - 2 \beta \gamma A^2}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Nuclear Fission Energy Balance|Binding Energy per Nucleon Curve|Energy Band Gap Temperature Dependency

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to couple nuclear energy release with local thermodynamic heating and solid-state temperature dependencies.

The primary trap (Option C) catches students who calculate the correct nuclear Q-value but fail to account for the adiabatic temperature spike in the micro-detector, incorrectly using the standard band gap Eg0E_{g0}.

Another trap (Option B) tests sign conventions, where students might incorrectly assume the band gap increases with temperature or misapply the negative gradient of the binding energy curve.

The problem rigorously demands the synthesis of the Binding Energy curve gradient to find Q, followed by applying Varshni's empirical-style band gap shift.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterNuclei - Class 12
ConceptNuclear Fission Energy Balance
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree