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Question #43823

Difficulty: 8/10 | 🟢 Free

The Question

A long, thin, non-conducting cylindrical shell of radius RR rotates about its longitudinal axis with a constant angular velocity ω0\omega_0. Initially (t=0t=0), the shell has a uniform linear number density N0N_0 of radioactive isotope AA (charge +q+q). Isotope AA undergoes a successive decay chain: A→B→CA \to B \to C, where the decay constant for A→BA \to B is 2λ2\lambda and for B→CB \to C is λ\lambda. Isotope BB has charge +2q+2q and Isotope CC has charge +4q+4q. All isotopes remain firmly attached to the rotating shell. A particle PP of mass mm and charge +Q+Q is constrained to move in a smooth, stationary, non-conducting circular tube of radius rr (r<Rr < R) coaxial with the cylinder. At t=0t=0, particle PP is at rest. Find the speed of particle PP at the exact instant when the number of BB nuclei on the shell reaches its maximum value. (Assume the system is in a vacuum and ignore any magnetic field produced by particle PP itself).

Options

  • A.

    5μ0ω0qQN0r16πm\frac{5 \mu_0 \omega_0 q Q N_0 r}{16 \pi m}

  • B.

    9μ0ω0qQN0r16πm\frac{9 \mu_0 \omega_0 q Q N_0 r}{16 \pi m}

  • C.

    3ln⁡2μ0ω0qQN0r8πm\frac{3 \ln 2 \mu_0 \omega_0 q Q N_0 r}{8 \pi m}

  • D.

    5μ0ω0qQN0r8πm\frac{5 \mu_0 \omega_0 q Q N_0 r}{8 \pi m}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Successive Decay Equilibrium|Induced Electric Fields|Vector Cross-Product

Why This Question Is Tricky

Common Mistakes

This question tests the coupling of probabilistic successive radioactive decay with classical electrodynamics via the Maxwell-Faraday law.

The primary trap lies in the non-conservative nature of the induced electric field.

Students often incorrectly attempt to calculate the instantaneous force at tmt_m and assume constant acceleration (leading to Option C), or they forget that the initial magnetic field at t=0t=0 is non-zero because the parent isotope A is already charged and rotating (leading to Option B).

The correct physical framework requires recognizing that the change in velocity is directly proportional to the change in magnetic flux (ΔB\Delta B), necessitating an integration of the Lorentz force over the decay time interval.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterNuclei - Class 12
ConceptSuccessive Decay Equilibrium
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree