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Question #43815
The Question
In a theoretical liquid-drop model, the binding energy per nucleon of a nucleus with mass number depends on a dimensionless deformation parameter as where , , and are positive constants in . The state corresponds to the stable spherical equilibrium of the nucleus. To induce nuclear fission, the nucleus must be deformed beyond its restoring stability limit. What is the minimum total kinetic energy that must be imparted to the deformation mode of the nucleus at to cause it to undergo fission?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Binding Energy per Nucleon Curve|Equilibrium Stability|Small Angle Approximation
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to map the binding energy per nucleon to a macroscopic potential energy landscape for the entire nucleus.
The primary trap is twofold: first, students often forget to multiply the binding energy per nucleon by the mass number to get the total energy of the system, leading to an answer off by a factor of (Option B).
Second, students accustomed to simple harmonic oscillators might incorrectly assume the restoring force is purely linear and fail to recognize that the cubic anharmonicity () creates a local maximum in the potential energy landscape, which defines the physical threshold for fission.
Misidentifying the peak of the potential barrier by setting instead of is another common lethal mistake that leads to Option C.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Nuclei - Class 12 |
| Concept | Binding Energy per Nucleon Curve |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |