Start Learning Free

Before You Begin

Question #43798

Difficulty: 8/10 | 🟢 Free

The Question

A hydrogen-like ion of mass MM and atomic number ZZ is initially at rest. It absorbs a photon and undergoes a transition from the ground state (n=1n=1) to the series limit (n=∞n=\infty), liberating the electron with zero kinetic energy. Let λ0\lambda_0 be the theoretical maximum wavelength of the photon required for this transition, assuming an infinitely massive nucleus. If λ\lambda is the actual maximum wavelength required when accounting for the recoil of the nucleus, which of the following expressions gives the magnitude of the wavelength shift ∣Δλ∣=λ0−λ|\Delta \lambda| = \lambda_0 - \lambda to the first order in the recoil correction? (Assume the internal atomic energy levels are unaffected by the finite mass of the nucleus, hh is Planck's constant, and cc is the speed of light).

Options

  • A.

    h2Mc\frac{h}{2Mc}

  • B.

    hMc\frac{h}{Mc}

  • C.

    hZ22Mc\frac{h Z^2}{2Mc}

  • D.

    h4Mc\frac{h}{4Mc}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Spectral Series Limits|Atomic Recoil|Conservation of Linear Momentum

Why This Question Is Tricky

Common Mistakes

Students often incorrectly assume that the photon energy exactly equals the atomic transition energy (Eγ=ΔEE_\gamma = \Delta E), ignoring the momentum carried by the photon.

When forced to consider recoil, a common trap is to misapply the Doppler effect sequentially—assuming the atom absorbs the photon, recoils with velocity v=ΔE/Mcv = \Delta E / Mc, and experiences a classical Doppler shift Δλ=λ0(v/c)=h/Mc\Delta \lambda = \lambda_0 (v/c) = h/Mc.

This sequential reasoning violates simultaneous conservation of energy and momentum.

By rigorously applying both conservation laws, the recoil kinetic energy K=p2/2MK = p^2/2M acts as an energy sink, requiring a higher-energy (shorter wavelength) incident photon.

The exact energy partition yields a wavelength shift of exactly half the Compton wavelength of the ion (h2Mc\frac{h}{2Mc}), exposing the flaw in the sequential Doppler approximation.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterAtoms - Class 12
ConceptSpectral Series Limits
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree