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Question #43794

Difficulty: 8/10 | 🟢 Free

The Question

A diatomic molecule is modeled as two point masses m1=mm_1 = m and m2=2mm_2 = 2m carrying charges +q+q and −q-q respectively. They are bound by an effective harmonic potential such that the internal restoring force is Fint=−K(x−x0)F_{\text{int}} = -K(x - x_0), where xx is their separation and x0x_0 is the natural equilibrium length. The molecule is placed in a non-uniform electric field E⃗=αzk^\vec{E} = \alpha z \hat{k} (where α>0\alpha > 0 is a constant). At t=0t=0, the center of mass of the molecule is at z=0z=0, and the masses are aligned along the z-axis with m1m_1 at a larger z-coordinate. The molecule is initially at rest with separation x=x0x = x_0. Assuming the molecule is very stiff (K≫qαK \gg q\alpha) such that the separation xx remains close to x0x_0, find the time-dependent quasi-equilibrium shift in the separation, Δx(t)=xeq(t)−x0\Delta x(t) = x_{\text{eq}}(t) - x_0, to leading order in 1/K1/K for t>0t > 0.

Options

  • A.

    qαx03K+q2α2x06mKt2\frac{q \alpha x_0}{3K} + \frac{q^2 \alpha^2 x_0}{6mK} t^2

  • B.

    qαx03K+q2α2x03mKt2\frac{q \alpha x_0}{3K} + \frac{q^2 \alpha^2 x_0}{3mK} t^2

  • C.

    qαx02K+q2α2x06mKt2\frac{q \alpha x_0}{2K} + \frac{q^2 \alpha^2 x_0}{6mK} t^2

  • D.

    qαx0K+q2α2x02mKt2\frac{q \alpha x_0}{K} + \frac{q^2 \alpha^2 x_0}{2mK} t^2

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Radius and Velocity Scaling|Center of Mass (COM) Frame|Electric Field Symmetry

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to analyze a two-body system in a non-uniform field, specifically targeting the misconception that a neutral system (like a dipole) in an external field has a static Center of Mass (COM).

Students often incorrectly assume the COM is an inertial frame and calculate the relative stretching force using only the initial static positions.

However, the field gradient α\alpha creates a net force on the dipole, causing the COM to accelerate.

This acceleration introduces a non-inertial pseudo-force in the COM frame (or equivalently, a time-dependent shift in the effective external force), which couples the macroscopic translation of the molecule to its microscopic internal separation.

The trap is failing to account for the dynamic Zcom(t)Z_{\text{com}}(t) in the reduced mass force equation.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterAtoms - Class 12
ConceptRadius and Velocity Scaling
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree