Start Learning Free

Before You Begin

Question #43790

Difficulty: 8/10 | 🟢 Free

The Question

Consider an n-type semiconductor at a low temperature TT (in the freeze-out regime) doped with a donor concentration NDN_D. The donor electrons can be modeled as quasi-hydrogen atoms. The semiconductor has a relative permittivity ϵr\epsilon_r and an effective electron mass m∗m^*. The ionization energy of a free hydrogen atom is E0E_0, and the free electron mass is mem_e. In this regime, the conduction electron concentration is given by n=NDNcexp⁡(−ΔE2kBT)n = \sqrt{N_D N_c} \exp\left(-\frac{\Delta E}{2k_B T}\right), where ΔE\Delta E is the donor ionization energy and NcN_c is the effective density of states in the conduction band. Assume Nc∝T3/2N_c \propto T^{3/2} and the electron mobility due to ionized impurity scattering scales as μ∝T3/2\mu \propto T^{3/2}. Which of the following expressions correctly represents the temperature coefficient of resistivity, α=1ρdρdT\alpha = \frac{1}{\rho}\frac{d\rho}{dT}, of this semiconductor?

Options

  • A.

    −(94T+E0m∗2meϵr2kBT2)-\left( \frac{9}{4T} + \frac{E_0 m^*}{2 m_e \epsilon_r^2 k_B T^2} \right)

  • B.

    −(34T+E0me2m∗ϵr2kBT2)-\left( \frac{3}{4T} + \frac{E_0 m_e}{2 m^* \epsilon_r^2 k_B T^2} \right)

  • C.

    94T+E0m∗2meϵr2kBT2\frac{9}{4T} + \frac{E_0 m^*}{2 m_e \epsilon_r^2 k_B T^2}

  • D.

    −(3T+E0m∗meϵr2kBT2)-\left( \frac{3}{T} + \frac{E_0 m^*}{m_e \epsilon_r^2 k_B T^2} \right)

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Energy Level Scaling|Law of Mass Action|Temperature Coefficient (Alpha)

Why This Question Is Tricky

Common Mistakes

This question tests the integration of quantum energy level scaling with macroscopic transport properties and the Law of Mass Action.

Students must first correctly scale the Bohr model for a donor impurity using effective mass and dielectric constant.

The primary trap lies in the temperature coefficient calculation: students often memorize α\alpha as a constant or calculate it for conductivity instead of resistivity (missing the overall negative sign).

Furthermore, they must correctly apply the square root from the Law of Mass Action to the temperature dependence of the effective density of states (Nc∝T3/2N_c \propto T^{3/2}), and combine it with the mobility temperature dependence to find the true scaling of resistivity before differentiating.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterAtoms - Class 12
ConceptEnergy Level Scaling
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree