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Question #43782

Difficulty: 8/10 | 🟢 Free

The Question

Consider a hypothetical atom consisting of a stationary nucleus of mass MM and charge +Ze+Ze, and an electron of mass mm and charge −e-e. Assume that both the electrostatic and gravitational forces between the nucleus and the electron are significant and act simultaneously. Using the Bohr model of quantization of angular momentum, determine the magnitude of the total energy of the electron in its nn-th allowed circular orbit. Let hh be Planck's constant, ℏ=h2π\hbar = \frac{h}{2\pi}, GG be the universal gravitational constant, and ϵ0\epsilon_0 be the permittivity of free space. All quantities are in SI units and the final energy is expressed in Joules (J\text{J}).

Options

  • A.

    m2n2ℏ2(Ze24πϵ0+GMm)2 J\frac{m}{2n^2\hbar^2} \left( \frac{Ze^2}{4\pi\epsilon_0} + GMm \right)^2 \, \text{J}

  • B.

    m2n2ℏ2((Ze24πϵ0)2+(GMm)2) J\frac{m}{2n^2\hbar^2} \left( \left(\frac{Ze^2}{4\pi\epsilon_0}\right)^2 + (GMm)^2 \right) \, \text{J}

  • C.

    m2n2ℏ2(Ze24πϵ0−GMm)2 J\frac{m}{2n^2\hbar^2} \left( \frac{Ze^2}{4\pi\epsilon_0} - GMm \right)^2 \, \text{J}

  • D.

    mn2ℏ2(Ze24πϵ0+GMm)2 J\frac{m}{n^2\hbar^2} \left( \frac{Ze^2}{4\pi\epsilon_0} + GMm \right)^2 \, \text{J}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Quantization of Angular Momentum|Gravitational Potential Energy (System)|Coulomb's Law Vector Form

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to apply the principle of superposition to central forces within the semi-classical Bohr model.

A common trap is treating the total energy of the system as the simple sum of the isolated electrostatic Bohr energy and the isolated gravitational Bohr energy (Option B).

This incorrectly assumes that Etotal∝αelec2+αgrav2E_{total} \propto \alpha_{elec}^2 + \alpha_{grav}^2, ignoring the cross-term 2αelecαgrav2\alpha_{elec}\alpha_{grav} that arises because the orbital radius itself depends on the combined effective coupling constant α=αelec+αgrav\alpha = \alpha_{elec} + \alpha_{grav}.

Another trap is misapplying the sign of the potential (Option C) or forgetting the virial theorem factor of 1/21/2 (Option D).

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterAtoms - Class 12
ConceptQuantization of Angular Momentum
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree