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Question #43780

Difficulty: 8/10 | 🟢 Free

The Question

An alpha particle of mass mm and charge +2e+2e is projected from infinity with an initial speed v0v_0 and an impact parameter bb towards a fixed heavy nucleus of charge +Ze+Ze located at the origin. The entire region contains a static, non-uniform magnetic field given by B⃗=B0(xai^−yaj^)\vec{B} = B_0 \left( \frac{x}{a} \hat{i} - \frac{y}{a} \hat{j} \right), where B0B_0 and aa are positive constants. Due to the combined electric and magnetic forces, the alpha particle follows a complex 3D trajectory. If rminr_{min} is the distance of closest approach to the nucleus, what is the speed vv of the alpha particle at this point of closest approach? (Assume the nucleus remains stationary, ϵ0\epsilon_0 is the vacuum permittivity, and ignore electromagnetic radiation).

Options

  • A.

    v02−Ze2πϵ0mrmin\sqrt{v_0^2 - \frac{Z e^2}{\pi \epsilon_0 m r_{min}}}

  • B.

    v0brmin\frac{v_0 b}{r_{min}}

  • C.

    v02−Ze2πϵ0mrmin−e2B02rmin2m2\sqrt{v_0^2 - \frac{Z e^2}{\pi \epsilon_0 m r_{min}} - \frac{e^2 B_0^2 r_{min}^2}{m^2}}

  • D.

    00

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Distance of Closest Approach|Moving Charge in Non-Uniform B

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to distinguish between conserved and non-conserved quantities in a complex field.

The presence of a non-uniform magnetic field breaks the central force symmetry, meaning the magnetic force exerts a torque about the origin (τ⃗=r⃗×(qv⃗×B⃗)≠0\vec{\tau} = \vec{r} \times (q\vec{v} \times \vec{B}) \neq 0).

Students falling into the trap will erroneously apply conservation of angular momentum to conclude v=v0b/rminv = v_0 b / r_{min}, or they will attempt to set up coupled Lorentz-Newton differential equations, leading to massive mathematical bloat.

The conceptual key is recognizing that a static magnetic field, regardless of its complexity or non-uniformity, does zero work.

Thus, the Work-Energy Theorem bypasses the trajectory's complexity, reducing the problem to pure mechanical energy conservation.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterAtoms - Class 12
ConceptDistance of Closest Approach
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree