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Question #43775

Difficulty: 8/10 | 🟢 Free

The Question

A fixed, uniformly charged oblate spheroid with total charge +Q+Q is centered at the origin of a Cartesian coordinate system. Its axis of rotational symmetry lies along the zz-axis. A point charge +q+q of mass mm is projected from a large distance (x→−∞x \to -\infty) with an initial velocity vector v⃗=v0i^\vec{v} = v_0 \hat{i}. The initial position of the particle is given by the coordinates (−∞,b,c)(-\infty, b, c), where bb and cc are positive distances. Let L⃗\vec{L} be the angular momentum vector of the particle about the origin. Which of the following correctly describes the conservation of angular momentum for this system during the particle's motion?

Options

  • A.

    dL⃗dt=0\frac{d\vec{L}}{dt} = 0 with ∣L⃗∣=mv0b2+c2|\vec{L}| = m v_0 \sqrt{b^2 + c^2}, because the electrostatic field of an isolated charge distribution is a central force field.

  • B.

    dLzdt=0\frac{dL_z}{dt} = 0 with Lz=−mv0bL_z = -m v_0 b, while dL⃗dt≠0\frac{d\vec{L}}{dt} \neq 0, because the electric field is azimuthally symmetric but non-central.

  • C.

    dLydt=0\frac{dL_y}{dt} = 0 with Ly=mv0cL_y = m v_0 c, while dL⃗dt≠0\frac{d\vec{L}}{dt} \neq 0, because the particle's initial velocity is orthogonal to the yy-axis.

  • D.

    dL⃗dt≠0\frac{d\vec{L}}{dt} \neq 0 and no individual Cartesian component of L⃗\vec{L} is conserved, because the oblate spheroid produces a non-uniform, non-spherical potential.

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Impact Parameter Geometry|Gauss Law Applicability|Shell Theorem (Internal vs External)

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to distinguish between central forces and azimuthally symmetric non-central forces.

A common trap is assuming that any isolated charge distribution can be treated as a point charge (yielding a central force field) where total angular momentum L⃗\vec{L} is conserved, leading students to incorrectly choose Option A.

Another trap is recognizing the non-spherical nature of the oblate spheroid but failing to apply Noether's theorem (or basic torque analysis) to realize that continuous rotational symmetry about the zz-axis guarantees the conservation of the zz-component of angular momentum (LzL_z).

By forcing the evaluation of r⃗×F⃗\vec{r} \times \vec{F}, the problem highlights that while E⃗\vec{E} is non-central (τ⃗≠0\vec{\tau} \neq 0), the absence of an azimuthal field component (Eϕ=0E_\phi = 0) ensures τz=0\tau_z = 0.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterAtoms - Class 12
ConceptImpact Parameter Geometry
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree