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Question #43770

Difficulty: 8/10 | 🟢 Free

The Question

An evacuated, non-conducting thin tube forms a semi-circle of radius RR in the xyxy-plane, extending from θ=0\theta = 0 to θ=π\theta = \pi. A photoelectric emitter is located at θ=0\theta = 0 and a collector is at θ=π\theta = \pi. A uniform time-varying magnetic field B⃗=αtk^\vec{B} = \alpha t \hat{k} (where α>0\alpha > 0 is a constant and k^\hat{k} is the unit vector out of the page) exists everywhere in the cylindrical region r≤Rr \le R. Monochromatic light of frequency ν\nu is incident on the emitter, which has a work function ϕ\phi. Electrons are emitted and constrained to travel through the tube to the collector. What is the minimum stopping potential V0V_0 (applied such that the collector is at a lower potential than the emitter) required to prevent the fastest electrons from reaching the collector? (Assume ee is the magnitude of the electron charge)

Options

  • A.

    hν−ϕe+πR2α2\frac{h\nu - \phi}{e} + \frac{\pi R^2 \alpha}{2}

  • B.

    hν−ϕe−πR2α2\frac{h\nu - \phi}{e} - \frac{\pi R^2 \alpha}{2}

  • C.

    hν−ϕe+πR2α\frac{h\nu - \phi}{e} + \pi R^2 \alpha

  • D.

    hν−ϕe\frac{h\nu - \phi}{e}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Stopping Potential Sign|Lorentz Force Vector Direction|Faraday’s Law Vector Form

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of the photoelectric effect, Faraday's law of induction, and the work-energy theorem involving non-conservative fields.

The primary trap lies in the sign convention and vector nature of the induced electric field.

Students often blindly subtract the induced EMF, assuming a 'back-EMF' always opposes motion.

However, Lenz's law dictates the direction of the induced electric field (clockwise here), and because the electron carries a negative charge, the resulting Lorentz force is counter-clockwise.

This force actually aids the electron's motion along the semi-circular path, doing positive work.

Consequently, a higher external stopping potential is required to halt the electron.

Furthermore, students must correctly integrate the non-conservative electric field over the semi-circular path rather than using the full-loop EMF.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterDual Nature of Radiation and Matter - Class 12
ConceptStopping Potential Sign
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree