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Question #43749

Difficulty: 8/10 | 🟢 Free

The Question

A reverse-biased silicon p-n junction is uniformly illuminated by monochromatic light of wavelength λ=620 nm\lambda = 620 \text{ nm} and intensity I=3.2 W/m2I = 3.2 \text{ W/m}^2. The incident photon flux Φ0\Phi_0 generates electron-hole pairs at a uniform volume rate G=αΦ0G = \alpha \Phi_0 throughout the device, where α=4×103 m−1\alpha = 4 \times 10^3 \text{ m}^{-1} is the absorption coefficient. The depletion region of the junction has a width W=2.0 \mumW = 2.0 \text{ \mu m}. The minority carrier diffusion lengths in the p-type and n-type neutral regions are Ln=8.0 \mumL_n = 8.0 \text{ \mu m} and Lp=15.0 \mumL_p = 15.0 \text{ \mu m}, respectively. Assuming steady-state conditions and that all minority carriers generated within one diffusion length of the depletion region reach the junction to contribute to the current, what is the magnitude of the total steady-state photocurrent density JphJ_{ph}?

(Take the energy of a photon as E=hcλE = \frac{hc}{\lambda}, hc=1240 eV⋅nmhc = 1240 \text{ eV}\cdot\text{nm}, and elementary charge e=1.6×10−19 Ce = 1.6 \times 10^{-19} \text{ C})

Options

  • A.

    160.0 mA/m2160.0 \text{ mA/m}^2

  • B.

    12.8 mA/m212.8 \text{ mA/m}^2

  • C.

    147.2 mA/m2147.2 \text{ mA/m}^2

  • D.

    1600 mA/m21600 \text{ mA/m}^2

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Photon Neutrality|Drift vs Diffusion Current|Intensity and Photon Flux

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to distinguish between the generation mechanism (photon flux) and the transport mechanisms (drift vs. diffusion) in an optoelectronic junction.

A common trap is assuming that only the strong electric field in the depletion region contributes to the photocurrent, leading students to calculate only the drift current (12.8 mA/m212.8 \text{ mA/m}^2).

Another misconception is equating the total incident photon flux directly to the current density (1600 mA/m21600 \text{ mA/m}^2), which ignores the continuity equation and the fact that only carriers generated within the effective collection length (W+Ln+LpW + L_n + L_p) can successfully reach the junction before recombining.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterDual Nature of Radiation and Matter - Class 12
ConceptPhoton Neutrality
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree