Start Learning Free

Before You Begin

Question #43745

Difficulty: 8/10 | 🟢 Free

The Question

A solid cylindrical pulley of mass MM and radius RR is suspended by a light inextensible string. One end of the string is attached to a rigid ceiling. The string passes under the pulley and its other end is attached to a vertical ideal spring of spring constant kk, which is also suspended from the ceiling. A linear polarizer is mounted on the flat circular face of the pulley such that it rotates with the pulley. Unpolarized light of intensity I0I_0 travels horizontally, parallel to the pulley's axis. It first passes through a fixed stationary polarizer with a vertical transmission axis, and then through the rotating polarizer on the pulley. At the equilibrium position of the pulley, the transmission axis of the rotating polarizer is also vertical. The pulley is displaced vertically downwards by a small distance AA from its equilibrium position and released from rest at t=0t=0. Assuming the string does not slip on the pulley, which of the following expressions represents the intensity of the transmitted light as a function of time tt?

Options

  • A.

    I02cos⁡2[ARcos⁡(2k3Mt)]\frac{I_0}{2} \cos^2\left[ \frac{A}{R} \cos\left( \sqrt{\frac{2k}{3M}} t \right) \right]

  • B.

    I02cos⁡2[ARcos⁡(8k3Mt)]\frac{I_0}{2} \cos^2\left[ \frac{A}{R} \cos\left( \sqrt{\frac{8k}{3M}} t \right) \right]

  • C.

    I0cos⁡2[ARcos⁡(8k3Mt)]I_0 \cos^2\left[ \frac{A}{R} \cos\left( \sqrt{\frac{8k}{3M}} t \right) \right]

  • D.

    I02cos⁡2[2ARcos⁡(4kMt)]\frac{I_0}{2} \cos^2\left[ \frac{2A}{R} \cos\left( \sqrt{\frac{4k}{M}} t \right) \right]

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Malus's Law|Dimensional Consistency|Effective Spring Constant|Vertical Oscillations

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of rotational kinematics, effective spring constants, and wave optics (Malus's Law).

The primary trap lies in the miscalculation of the effective spring constant and effective mass.

Students often incorrectly assume the spring extends by xx instead of 2x2x, leading to a missing factor of 4 in the restoring force (keff=kk_{eff} = k instead of 4k4k).

Additionally, they may neglect the rotational kinetic energy of the pulley, using MM instead of 3M/23M/2.

Finally, a secondary trap exists in forgetting that the first polarizer halves the intensity of the unpolarized light, testing their rigorous application of Malus's Law from the source to the observer.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWave Optics - Class 12
ConceptMalus's Law
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree