Start Learning Free

Before You Begin

Question #43743

Difficulty: 8/10 | 🟢 Free

The Question

An unpolarized light beam traveling in a vacuum (refractive index n1=1n_1 = 1) is incident on a flat dielectric surface (refractive index n2=3n_2 = \sqrt{3}) at the Brewster angle θB\theta_B. Let ⟨S⃗R⟩\langle \vec{S}_R \rangle and ⟨S⃗T⟩\langle \vec{S}_T \rangle represent the time-averaged Poynting vectors of the reflected and transmitted beams, respectively. Calculate the ratio of their magnitudes, ∣⟨S⃗R⟩∣∣⟨S⃗T⟩∣\frac{|\langle \vec{S}_R \rangle|}{|\langle \vec{S}_T \rangle|}.

Options

  • A.

    37\frac{\sqrt{3}}{7}

  • B.

    17\frac{1}{7}

  • C.

    18\frac{1}{8}

  • D.

    37\frac{3}{7}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Brewster's Law|Magnitude Ratio Identity|Vector Cross-Products

Why This Question Is Tricky

Common Mistakes

This question tests the misconception that the magnitude of the Poynting vector (intensity) is a conserved scalar quantity across a boundary (I0=IR+ITI_0 = I_R + I_T).

Students who make this error will calculate IT=I0−I0/8=7I0/8I_T = I_0 - I_0/8 = 7I_0/8, leading to the incorrect ratio of 1/71/7.

The correct physical principle requires applying conservation of energy to the normal component of the Poynting vector (S⃗⋅n^\vec{S} \cdot \hat{n}), which accounts for the change in the beam's cross-sectional area due to refraction (cos⁡θi\cos \theta_i vs cos⁡θt\cos \theta_t).

Furthermore, it tests the knowledge that at Brewster's angle, unpolarized light yields a purely s-polarized reflected beam, requiring the use of Fresnel equations rather than simple scalar assumptions.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWave Optics - Class 12
ConceptBrewster's Law
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree