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Question #43740

Difficulty: 8/10 | 🟢 Free

The Question

Unpolarized light is incident from a transparent solid medium of dielectric constant K1=2K_1 = 2 onto the flat surface of a liquid. Initially, in the absence of any external electric field, the reflected light is found to be completely plane-polarized when the angle of incidence is θ0=60∘\theta_0 = 60^\circ. A uniform electric field E=2×104 V/mE = 2 \times 10^4 \text{ V/m} is then applied throughout the liquid. Due to the Kerr effect, the liquid remains optically isotropic but its dielectric constant shifts according to the relation K2(E)=K20+αE2K_2(E) = K_{20} + \alpha E^2, where K20K_{20} is the zero-field dielectric constant and α=5×10−9 m2/V2\alpha = 5 \times 10^{-9} \text{ m}^2/\text{V}^2. Assuming the magnetic permeability of both media is equal to μ0\mu_0, what is the new angle of incidence θ1\theta_1 at which the reflected light is completely plane-polarized?

Options

  • A.

    tan⁡−1(2)\tan^{-1}(2)

  • B.

    tan⁡−1(5)\tan^{-1}(\sqrt{5})

  • C.

    tan⁡−1(4)\tan^{-1}(4)

  • D.

    tan⁡−1(22)\tan^{-1}(2\sqrt{2})

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Correct Answer

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Brewster's Law|Dielectric Constant (K) Shift|Medium Dependency

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of Wave Optics (Brewster's Law) and Electrostatics (dielectric properties), specifically targeting two common misconceptions.

First, students frequently memorize Brewster's law as tan⁡θp=n\tan \theta_p = n, implicitly assuming the incident medium is a vacuum or air.

If they apply this here, they will incorrectly calculate the initial dielectric constant as K20=3K_{20} = 3 and select the trap option tan⁡−1(5)\tan^{-1}(\sqrt{5}).

Second, students often confuse the linear relationship of the refractive index ratio with the dielectric constant, mistakenly using tan⁡θp=K2/K1\tan \theta_p = K_2/K_1 instead of K2/K1\sqrt{K_2/K_1}, leading to the trap option tan⁡−1(4)\tan^{-1}(4).

The problem demands rigorous application of Fresnel's boundary conditions where the relative refractive index dictates the polarization angle.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWave Optics - Class 12
ConceptBrewster's Law
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree