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Question #43732

Difficulty: 8/10 | 🟢 Free

The Question

A monochromatic point source SS emitting light of proper wavelength λ\lambda is placed on the principal axis of a Young's Double Slit apparatus having two identical slits. The source is at a large distance from the slits. At t=0t=0, the source starts accelerating towards the slits with a time-dependent acceleration a(t)=αta(t) = \alpha t, where α\alpha is a positive constant. A small detector is fixed on the screen at a point PP which initially coincides with the nn-th order bright fringe (n≫1n \gg 1). Assuming the speed of the source remains much less than the speed of light cc during the observation, and ignoring the light travel time, at what time tt will the detector record a zero intensity for the first time?

Options

  • A.

    cnα\sqrt{\frac{c}{n \alpha}}

  • B.

    2cnα\sqrt{\frac{2c}{n \alpha}}

  • C.

    c2nα\sqrt{\frac{c}{2 n \alpha}}

  • D.

    cα\sqrt{\frac{c}{\alpha}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Diffraction vs Interference|Young's Double Slit Geometry|Non-Uniform Acceleration Constraint|Approximation (Binomial)

Why This Question Is Tricky

Common Mistakes

This question tests the coupling of kinematics with wave optics and the Doppler effect.

A common trap is misapplying the phase difference condition by assuming a full 2π2\pi phase shift is needed for zero intensity (leading to option B), or incorrectly integrating the non-uniform acceleration as v=αt2v = \alpha t^2 without the factor of 1/21/2 (leading to option C).

Furthermore, students often incorrectly expand the time-dependent phase difference Δϕ(t)=2πn(1−v/c)−1\Delta \phi(t) = 2\pi n (1 - v/c)^{-1} by dropping the fringe order nn in the variable term (leading to option D).

The problem requires a rigorous transition from a static geometric path difference to a dynamic, time-dependent phase analysis using the binomial approximation.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWave Optics - Class 12
ConceptDiffraction vs Interference
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree