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Question #43729

Difficulty: 8/10 | 🟢 Free

The Question

A modified Young's Double Slit Experiment setup consists of two narrow slits S1S_1 and S2S_2 located at coordinates (0,d/2)(0, d/2) and (0,−d/2)(0, -d/2) respectively. A screen is placed at x=Dx = D. The space between the slits and the screen (0≤x≤D0 \le x \le D) is filled with a non-uniform transparent dielectric medium whose refractive index varies with the transverse coordinate yy as μ(y)=μ0+ky\mu(y) = \mu_0 + k y, where μ0\mu_0 and kk are positive constants. Light of vacuum wavelength λ\lambda is incident on the slits. Assuming d≪Dd \ll D, y≪Dy \ll D, ky≪μ0k y \ll \mu_0, and that the rays travel in approximately straight lines due to the weak gradient, what is the yy-coordinate of the central maximum (where the optical path difference is zero) on the screen?

Options

  • A.

    kD22μ0\frac{k D^2}{2\mu_0}

  • B.

    kD2μ0\frac{k D^2}{\mu_0}

  • C.

    kD24μ0\frac{k D^2}{4\mu_0}

  • D.

    2kD2μ0\frac{2k D^2}{\mu_0}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Intensity Distribution in YDSE|Non-Uniform Dielectric Filling|Optical Path Difference

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to apply the Superposition Principle and calculate phase differences in a continuously varying dielectric medium, which dictates the spatial redistribution of energy (interference pattern).

A common lethal mistake is assuming the optical path difference introduced by the medium is simply the difference in refractive index at the slits multiplied by the distance D (i.e., Δxmed=Δμ⋅D=kdD\Delta x_{med} = \Delta \mu \cdot D = k d D).

This ignores the fact that the rays converge to a single point on the screen, meaning they traverse a varying refractive index profile.

By failing to integrate μ(y)\mu(y) along the actual ray paths, students miss the averaging effect that introduces a critical factor of 1/21/2, leading them directly to the trap answer kD2μ0\frac{k D^2}{\mu_0}.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWave Optics - Class 12
ConceptIntensity Distribution in YDSE
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree