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Question #43728

Difficulty: 8/10 | 🟢 Free

The Question

A point source SS of monochromatic light (λ=600 nm\lambda = 600 \text{ nm}) is placed on the principal axis of an equiconvex lens at a distance of 18 cm18 \text{ cm}. The lens has a refractive index μ=1.5\mu = 1.5, radius of curvature R=24 cmR = 24 \text{ cm} for both surfaces, and its back surface is silvered. The lens has a circular aperture of diameter a=1.5 mma = 1.5 \text{ mm}. The light reflected from the silvered lens forms an image S′S' which acts as the source for a Young's Double Slit Experiment. The double slit plane is placed at a distance of 29 cm29 \text{ cm} from the lens (on the same side as SS). The slit separation is d=8.0 mmd = 8.0 \text{ mm}. A screen is placed at a distance D2=1.0 mD_2 = 1.0 \text{ m} from the double slit. If the source SS is given a small transverse displacement y0=1.2 mmy_0 = 1.2 \text{ mm} perpendicular to the principal axis, what is the observable shift of the central maximum on the screen?

Options

  • A.

    3.0 mm3.0 \text{ mm}

  • B.

    6.0 mm6.0 \text{ mm}

  • C.

    0.0 mm0.0 \text{ mm}

  • D.

    1.5 mm1.5 \text{ mm}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Central Fringe Shift|Lens Silvering Logic|Resolving Power Limits

Why This Question Is Tricky

Common Mistakes

Students often blindly apply the fringe shift formula Δy=(D2/D1)y′\Delta y = (D_2/D_1) y' without considering the physical boundaries of the light beam.

The trap lies in the dynamic aperture limitation: the finite diameter of the silvered lens restricts the cone angle of the reflected light.

By calculating the geometric spread of the beam at the slit plane, one finds it is narrower than the slit separation.

Furthermore, tracking the transverse shift of the beam reveals that the light cone completely misses both slits.

Consequently, the light physically cannot illuminate the slits, meaning no interference pattern is formed and the observable shift is zero.

This tests the transition from abstract wave optics formulas to the physical limits of optical systems.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWave Optics - Class 12
ConceptCentral Fringe Shift
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree