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Question #43708

Difficulty: 8/10 | 🟢 Free

The Question

A stationary nucleus of mass 2m2m undergoes nuclear fission into two identical fragments, each of mass mm. The total mass defect of the reaction corresponds to an energy equivalent QQ. During the fission process, a gamma-ray photon of energy EγE_\gamma is emitted. Assume the momentum carried by the gamma-ray photon is negligible. One of the fission fragments enters a medium where it experiences a velocity-dependent drag force of magnitude Fd=kv2F_d = kv^2 (where kk is a positive constant and vv is the instantaneous velocity) in addition to a constant kinetic friction force of magnitude fk=μmgf_k = \mu mg, where μ\mu is the coefficient of kinetic friction and gg is the acceleration due to gravity. Which of the following expressions gives the total distance xx traveled by this fragment before coming to rest?

Options

  • A.

    m2kln⁡(1+k(Q−Eγ)μm2g)\frac{m}{2k} \ln\left( 1 + \frac{k (Q - E_\gamma)}{\mu m^2 g} \right)

  • B.

    m2kln⁡(1+kQμm2g)\frac{m}{2k} \ln\left( 1 + \frac{k Q}{\mu m^2 g} \right)

  • C.

    m(Q−Eγ)2[k(Q−Eγ)+μm2g]\frac{m(Q - E_\gamma)}{2[k(Q - E_\gamma) + \mu m^2 g]}

  • D.

    m2kln⁡(1+2k(Q−Eγ)μm2g)\frac{m}{2k} \ln\left( 1 + \frac{2k (Q - E_\gamma)}{\mu m^2 g} \right)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Nuclear Fission Energy Balance|Work Done by Friction|Work-Energy Theorem Validity

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to synthesize nuclear energy balance with non-uniform mechanics.

A common trap is blindly applying the Work-Energy Theorem assuming a constant drag force (e.g., evaluating drag only at the initial velocity), which ignores the path-dependent nature of Fd=−kv2F_d = -kv^2 and bypasses the necessary differential equation vdvdxv \frac{dv}{dx}.

Additionally, students often fail to subtract the gamma-ray emission energy EγE_\gamma from the total mass-defect QQ-value, incorrectly assuming all nuclear energy manifests as mechanical kinetic energy of the fragments.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterNuclei - Class 12
ConceptNuclear Fission Energy Balance
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree