Start Learning Free

Before You Begin

Question #43705

Difficulty: 8/10 | 🟢 Free

The Question

A system of mass 6m6m is initially at rest in the laboratory frame. It explodes into three fragments AA, BB, and CC of masses mm, 2m2m, and 3m3m respectively. The total kinetic energy released in the explosion is QQ. If fragment CC is observed to have a kinetic energy of Q6\frac{Q}{6}, what is the maximum possible kinetic energy of fragment AA in the laboratory frame?

Options

  • A.

    9+4218Q\frac{9 + 4\sqrt{2}}{18} Q

  • B.

    59Q\frac{5}{9} Q

  • C.

    49Q\frac{4}{9} Q

  • D.

    9−4218Q\frac{9 - 4\sqrt{2}}{18} Q

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Energy Distribution in Beta Decay|Center of Mass (COM) Frame|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to analyze a 3-body explosion (kinematically analogous to beta decay) by transforming between the Laboratory frame and the Center of Mass (COM) frame of the remaining two fragments.

The primary trap is assuming that the remaining energy (5Q/65Q/6) is distributed between fragments A and B as if they were decaying from rest in the lab frame, which incorrectly yields 5Q/95Q/9 (Option B).

Students often fail to recognize that the momentum carried away by fragment C forces the COM of A and B to recoil.

To correctly solve for the maximum kinetic energy, one must isolate the internal kinetic energy of the A-B system by subtracting the translational kinetic energy of their COM, find the velocity of A in this COM frame, and then vectorially add it to the COM velocity.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterNuclei - Class 12
ConceptEnergy Distribution in Beta Decay
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree