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Question #43701

Difficulty: 8/10 | 🟢 Free

The Question

In a phenomenological model of a heavy nucleus of radius RR, the effective potential energy of a single nucleon at a distance rr from the center (0<r≤R0 < r \le R) is given by: U(r)=−U0[1−(rR)2]+kr2U(r) = -U_0 \left[ 1 - \left(\frac{r}{R}\right)^2 \right] + \frac{k}{r^2} where U0U_0 and kk are positive constants. The first term represents the attractive mean field of the saturated nuclear matter, and the second term represents a hard-core repulsion. A nucleon is initially at its stable equilibrium position r0r_0 inside the nucleus. What is the minimum external work required to move this nucleon slowly to the nuclear surface (r=Rr = R)? Assume the nucleus remains otherwise unperturbed.

Options

  • A.

    (U0−kR)2\left( \sqrt{U_0} - \frac{\sqrt{k}}{R} \right)^2

  • B.

    U0+kR2U_0 + \frac{k}{R^2}

  • C.

    U0−kR2U_0 - \frac{k}{R^2}

  • D.

    (U0+kR)2\left( \sqrt{U_0} + \frac{\sqrt{k}}{R} \right)^2

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Nuclear Force Range and Saturation|Conservative Force Field|Calculus (Potential Energy Gradient)

Why This Question Is Tricky

Common Mistakes

This question tests the application of conservative force fields within a phenomenological nuclear model.

A common misconception is confusing the 'saturation' of nuclear forces (constant binding energy per nucleon across different nuclei) with a constant spatial potential inside a single nucleus.

Students often incorrectly assume the interior force is zero everywhere or ignore the hard-core repulsion's role in establishing a local equilibrium.

By applying the Work-Energy Theorem to a conservative field, the work is strictly the potential difference ΔU\Delta U.

The trap is failing to find the true equilibrium position r0r_0 where dU/dr=0dU/dr = 0, and instead assuming r0=0r_0 = 0 or misinterpreting the saturation term, which leads to incorrect work values like U0+k/R2U_0 + k/R^2.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterNuclei - Class 12
ConceptNuclear Force Range and Saturation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree