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Question #43700

Difficulty: 8/10 | 🟢 Free

The Question

In a geological rock sample, the ratio of the number of stable daughter nuclei (NdN_d) to the number of radioactive parent nuclei (NpN_p) is measured to be R=NdNp=15.0±0.48R = \frac{N_d}{N_p} = 15.0 \pm 0.48. It is assumed that the sample initially contained no daughter nuclei and that all daughter nuclei present are solely due to the decay of the parent nuclei. If the decay constant λ\lambda of the parent nuclei is known exactly, what is the percentage error in the estimated age tt of the rock sample?

Options

  • A.

    34ln⁡2%\frac{3}{4 \ln 2} \%

  • B.

    3.2 %

  • C.

    3.0 %

  • D.

    165ln⁡15%\frac{16}{5 \ln 15} \%

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Activity Units and Transitions|Relative Error Propagation in Powers|Significant Figures|Approximation

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to correctly propagate errors through non-linear (specifically logarithmic) functions in a physical context.

A common lethal trap is applying linear relative error propagation directly to the ratio (Δtt=ΔRR\frac{\Delta t}{t} = \frac{\Delta R}{R}), which yields 3.2%3.2\%.

Another trap is ignoring the +1+1 in the logarithmic argument, leading to ΔRRln⁡R\frac{\Delta R}{R \ln R}.

The correct approach requires differentiating the exact relationship t=1λln⁡(R+1)t = \frac{1}{\lambda} \ln(R+1) to find the absolute error dtdt, and then dividing by tt to find the relative error, demonstrating that logarithmic sensitivity heavily suppresses the relative error as tt increases.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterNuclei - Class 12
ConceptActivity Units and Transitions
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree